Answer:
Step-by-step explanation:
12:15
I am going to assume that x2 = x squared
So: X^2 + 3x -40
= (X+8)(X-5)=0
X+8 = 0
X= - 8
The other solution is X -5 = 0
X = 5
Therefore the solution set is {-8, 5}
<span>The dimension of the rectangle would be length=#4/sqrt3# and width =4-#4/3= 8/3#
Explanation:
Let one vertex on the x axis be x, then the other vertex would be -x. Length of the rectangle would be thus 2x and width would be #4-x^2#
Area of the rectangle would be A=#2x(4-x^2)= 8x-2x^3#
For maximum area #(dA)/dx=0=8-6x^2#, which gives x=#2/sqrt3#
The dimension of the rectangle would be length=#4/sqrt3# and width =4-#4/3= 8/3#
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Last one, the line I as solid so it is greater tan or less than. it's shaded above so y is greater
Answer:
Step-by-step explanation:
the consecutive numbers can be represented by (n-1), n, and (n+1), where n is an integer.
(n-1) + n + (n+1) = 201
3n = 201
n = 67
66, 67, 68
