We know that
speed=distance/time
solve for time
time=distance/speed
in this problem
<span>Marco runs at a rate of 6 miles per hour.
</span><span>Fernando funs at a rate of 7.2 miles per hour
Difference=7.2-6=1.2 miles/hour
so
speed=1.2 miles/hour
distance=0.3 miles
time=?
</span>time=distance/speed-----> 0.3/1.2-----> 0.25 hour-----> 0.25*60=15 minutes
<span>
the answer is
0.25 hour (15 minutes)
Alternative Method
Let
x---------> Fernando's distance when Marco is 0.3 miles apart
</span>Fernando funs at a rate of 7.2 miles per hour
<span>for distance =x
time=x/7.2------> equation 1
</span>Marco runs at a rate of 6 miles per hour.
for distance=x-0.30
time=(x-0.30)/6------> equation 2
equate equation 1 and equation 2
7.2*(x-0.3)=6x-----> 7.2x-2.16=6x
7.2x-6x=2.16------> x=2.16/1.2-------> x=1.8 miles
time=x/7.2-----1.8/7.2=0.25 hour
Answer:
a.) 20 kilometers
b.)1.67 hours
Step-by-step explanation:
a.) formula= speed =distance/time
Speed= 10km/hr
Distance=unknown
Time=2hrs
Therefore from formula, distance=speed x time
10 x 2
20 kilometers
b.) If average speed is increased by 2km/hr then
total speed= 2+10=12km/hr
Distance remains constant therefore distance= 20km
Therefore time =distance/speed
20/12
= 1.67 hours
Answer:
WHAT ON EARTH
Step-by-step explanation:
Answer:
See attached picture.
Step-by-step explanation:
Graph and test solutions to create the shaded region.
The answer is fill its tanks with air so it floats to the top, but I will solve for the distance since I am nice
so we do
decent means negative
cimb=positive
add
decends 45 and 1/2
-45 and 1/2
climbs 39
+39
decedns 18 and 3/4
-18 and 3/4
add
-45 and 1/2+39-18 and 3/4
add
convert 1/2 to 2/4
gropu negatives
-45 and 2/4-18 and 3/4+39
add
-63 and 5/4+39
-64 and 1/4+39
-25 and 1/4
that is how far dow the submarine is
so the submarine needs to gu 25 and 1/4 ft up to reach the csurface
