Ask question

Ask question

All categories

ivanzaharov [21]

3 years ago

11

A testing instrument that's used to measure electrical signals in a circuit and display them as waveforms on a screen is called

a/an

1 answer:

disa [49]3 years ago

8 0

A testing instrument that's used to measure electrical signals
in a circuit and display them as waveforms on a screen is called
an oscilloscope.

You might be interested in

A 120-V rms voltage at 1000 Hz is applied to an inductor, a 2.00-μF capacitor and a 100-Ω resistor, all in series. If the rms va

natima [27]

Answer:

The inductance of the inductor is 35.8 mH

Explanation:

Given that,

Voltage = 120-V

Frequency = 1000 Hz

Capacitor $C= 2.00\mu F$

Current = 0.680 A

We need to calculate the inductance of the inductor

Using formula of current

$I = \dfrac{V}{Z}$

$Z=\sqrt{R^2+(L\omega-\dfrac{1}{C\omega})^2}$

Put the value of Z into the formula

$I=\dfrac{V}{\sqrt{R^2+(L\omega-\dfrac{1}{C\omega})^2}}$

Put the value into the formula

$0.680=\dfrac{120}{\sqrt{(100)^2+(L\times2\pi\times1000-\dfrac{1}{2\times10^{-6}\times2\pi\times1000})^2}}$

$L=35.8\ mH$

Hence, The inductance of the inductor is 35.8 mH

4 0

3 years ago

Read 2 more answers

What is the focal length (in meters) of a lens whose radius of curvature is 9. 2 m and has a refractive index 1. 2?

Fed [463]

The focal length (in meters) of a lens whose radius of curvature is 9. 2 m and has a refractive index 1.2 will be 18.4 m

The focal length of a lens is determined when the lens is focused at infinity. Lens focal length tells us the angle of view—how much of the scene will be captured—and the magnification—how large individual elements will be.

Focal length of a lens is the distance between center of lens and focal point . Focal point is a point on principal axis , at which light rays parallel to principal axis meet after refraction through lens or seem to meet after refraction .

The radius of curvature is the radius of sphere formed by the convex or concave mirror. It is also equal to the distance between the pole and center of curvature. The sign convention for focal length and radius of curvature is the same.

focal length = 2 * radius of curvature

given

radius of curvature = 9.2 m

focal length = 2 * 9.2

= 18.4 m

To learn more about focal length here

brainly.com/question/16188698

#SPJ4

4 0

1 year ago

A person holds a rifle horizontally and fires at a target. The bullet leaves the muzzle of the rifle with a velocity of 460 m/s.

Trava [24]

Answer:

the distance travelled from the bullet to the target is 391m

Explanation:

Hello! To solve this exercise we must follow the following steps.

1. the bullet travels with constant speed which means that the distance traveled to the target is given by the following equation

X=(V1)(T1)

$T1=\frac{X}{V1} =\frac{x}{460}$

where

X=target distance

V1=bullet speed=460m/s

T1=

time it takes for the bullet to reach the target

2. The distance the sound travels is given by the following equation (it is the same as the distance from the person to the target)

X=(V2)(T2)

$T2=\frac{X}{V2} =\frac{x}{340}$

X=

target distance

V2= speed of sound=340m/s

T2= time it takes the sound of the Bullet to return.

3. The total time it takes for the person to hear the bullet(T=2s) is the sum of the time it takes for the bullet to reach the target, plus the time it takes for the sound to reach the person, with the above we infer the following equation

T=T1+T2

2=T1+T2

4. Finally we use the equations found in step 1 and 2 to find the distance traveled using algebra.

$2=\frac{x}{340}+\frac{x}{460} \\x(\frac{1}{340} +\frac{1}{460} )=2\\\ X= \frac{2}{(\frac{1}{340} +\frac{1}{460} )} \\\\x=391m$

the distance travelled from the bullet to the target is 391m

3 0

2 years ago

Write .00000023 in scientific notation

Vikki [24]

Answer: 2.3 x 10^-7

Explanation:

When you move the decimal to the right, you decrease the exponent. So lets count how many spots you have to move the decimal spot to get an answer between 1 and 10. I counted seven spots.

So:

$2.3 *10^-^7$

8 0

2 years ago

Read 2 more answers

Astronomers have divided the planets into two groups. The inner, “terrestrial,” planets are Mercury, Venus, Earth, and Mars. The

algol [13]

Answer:

it's letter C because inner planets are warmer because they are close to the sun and they are smaller than the Jovian or Giant Gas Planets which have rings, and cooler.

3 0

2 years ago