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Answer:
The kinetic energy of the bullet is 5.4 × 10³ J
Explanation:
Hi there!
The equation of kinetic energy is the following:
KE = 1/2 · m · v²
Where:
KE = kinetic energy.
m = mass of the bullet.
v = speed of the bullet.
Let´s convert the mass unit to kg so that our result is in Joules:
64 g · ( 1 kg / 1000 g) = 0.064 kg
Then, the kinetic energy will be the following:
KE = 1/2 · 0.064 kg · (411 m/s)²
KE = 5.4 × 10³ J
Answer
given,
high temperature reservoir (T_c)= 464 K
efficiency of reservoir (ε)= 25 %
temperature to decrease = ?
increase in efficiency = 42 %
now, using equation
T_C = 348 K
now,
if the efficiency is equal to 42$ = 0.42
