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bezimeni [28]
3 years ago
13

A white blood cell has a diameter of approximately 12 micrometers or 0.012 um a model represents its diameter as 24 um what rati

o of model size
Physics
1 answer:
ohaa [14]3 years ago
3 0

Answer:

The ratio of the model size is 1 : 2000

Explanation:

Given

Real Diameter =  0.012 um

Scale Diameter =  24 um

Required

Determine the scale ratio

The scale ratio is calculated as follows;

Scale = \frac{Real\ Measurement}{Scale\ Measurement}

Substitute values for real and scale measurements

Scale = \frac{0.012\ um}{24\ um}

Divide the numerator and the denominator by 0012um

Scale = \frac{1}{2000}

Represent as ratio

Scale = 1 : 2000

<em>Hence, the ratio of the model size is 1 : 2000</em>

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A ball of mass m is thrown into the air in a 45° direction of the horizon, after 3 seconds the ball is seen in a direction 30° f
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Answer:

Velocity (magnitude) is 98.37 m/s

Explanation:

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v_{y}=v_{0y}+a*t=\frac{\sqrt{2} }{2}v_0-9.8t

Now we need to find v_y as a function of v_0. We use the horizontal velocity, which is always the same as follow:

v_x=v_0cos(45\º)=\frac{\sqrt{2} }{2}v_0=v_{t=3}*cos(30\º) \\

We know the angle at 3 seconds:

v_y(t=3)=v_{t=3}*sin(30\º)\\v_{t=3}=\frac{v_y}{sin(30\º)}

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\frac{\sqrt{2} }{2}v_0=\frac{v_y*cos(30\º) }{sin(30\º)} \\v_y=\frac{\sqrt{6} }{6}v_0

With this expression we go back to the kinematic equation and solve it for initial speed

\frac{\sqrt{6} }{6} v_0 =\frac{\sqrt{2} }{2}v_0-29.4\\v_0(\frac{\sqrt{6}-3\sqrt{2}}{6} )=-29.4\\v_0=98.37 m/s

3 0
3 years ago
A 2 nC point charge is at the origin, and a second 5 nC point charge is on the x-axis at x = 8 m. Find the electric field (magni
dimaraw [331]

Answer:

The magnitude of  the electric field is 5.75 N/C towards positive x- axis.

Explanation:

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Point charge at origin = 2 nC

Second charge = 5 nC

Distance at x axis = 8 m

We need to calculate the electric field at the point x = 2 m

Using formula of electric field

E=\dfrac{1}{4\pi\epsilon_{0}}(\dfrac{q_{1}}{r_{1}^2}+\dfrac{q_{2}}{r_{2}^2})

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E=9\times10^{9}\times(\dfrac{2\times10^{-9}}{2^2}+\dfrac{5\times10^{-9}}{(8-2)^2})

E=5.75\ N/C

The direction is toward positive x- axis.

Hence, The magnitude of  the electric field is 5.75 N/C towards positive x- axis.

7 0
3 years ago
A 12.0-g bullet is fired horizontally into a 112-g wooden block that is initially at rest on a frictionless horizontal surface a
sergiy2304 [10]
The speed would be in a decimal? Or do you want it in a fraction?
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Jaime lifts a package weighing 75N. if she lifts it 1.2 m, what work has she done
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Answer:
90 J
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3 years ago
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