3 years ago

If you get this right I will mark you as a brainliest

Mathematics

1 answer:

WARRIOR [948]3 years ago

5 0

I think it's a but I'm not for sure

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Simplify the following expression. *<br> 3(x-4)

damaskus [11]

Answer:

3x-12

Step-by-step explanation:

3(x-4)

Distribute

3x -3*4

3x-12

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4 years ago

You can buy jars of olives in two sizes.

Lemur [1.5K]

Jar A has better value, as it has more grams of olives for every dollar.

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3 years ago

Please help If a triangle a b c has a degree of 90 what the other ones = and what kind of triangle.

AleksAgata [21]

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3 years ago

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3 years ago

Can some one solve this pls<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D_0%20%5Cfrac%7B

zalisa [80]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$x(t)=sin(t)\\\\dx=cos(t)dt\\\\\text{For x = }\dfrac{1}{\sqrt{2}}=\dfrac{\sqrt{2}}{2} \text{ we have } t = \dfrac{\pi}{4}$

So, we can write.

$\displaystyle \int\limits^{\dfrac{1}{\sqrt{2}}}_0 {\dfrac{1}{\sqrt{1-x^2}}} \, dx =\int\limits^{\dfrac{\pi}{4}}_0 {\dfrac{cos(t)}{\sqrt{1-sin^2(t)}}} \, dt\\\\=\int\limits^{\dfrac{\pi}{4}}_0 {\dfrac{cos(t)}{\sqrt{cos^2(t)}}} \, dt\\\\=\int\limits^{\dfrac{\pi}{4}}_0 {\dfrac{cos(t)}{cos(t)}} \, dt \\\\=\int\limits^{\dfrac{\pi}{4}}_0 {1} \, dt\\\\=\large \boxed{\sf \bf \dfrac{\pi}{4}}$

Thank you

8 0

3 years ago

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