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3 years ago

The length of a rectangle is twice as long as the width. The area is 200 ft2. Find the length and the width of the rectangle.

Mathematics

1 answer:

DENIUS [597]3 years ago

7 0

Length is 20ft, width is 10ft

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This is equations and graph. Please answer correctly :(

miss Akunina [59]

1. y= -x + 3

2. y = x - 3

3. y = 3x + 1

4. y = -3x - 3

7 0

2 years ago

The volume of cylinder is 448 pie cm cube and height 7 cm find its radius

Verizon [17]

Answer:

$r =\bf 8 \space\ cm$

Step-by-step explanation:

The formula for volume of a cylinder is as follows:

$\boxed{Volume = \pi r^2 h}$

where:

• r = radius (? cm)

• h = height (7 cm).

Substituting the values into the formula:
$448 \pi = \pi \times r^2 \times 7$

Now solve for $r$ :

⇒ $r^2 = \frac{448 \pi }{\pi \times 7}$

⇒ $r = \sqrt{64}$

⇒ $r =\bf 8 \space\ cm$

8 0

2 years ago

Read 2 more answers

Please help mee pleaseee

nalin [4]

Answer:

The exact answer in terms of radicals is $x = 5*\sqrt[3]{25}$

The approximate answer is $x \approx 14.62009$ (accurate to 5 decimal places)

===============================================

Work Shown:

Let $y = \sqrt[5]{x^3}$

So the equation reduces to -7 = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

-----------

Since $y = \sqrt[5]{x^3}$ and y = 5, this means we can equate the two expressions and solve for x

$y = 5$

$\sqrt[5]{x^3} = 5$

$x^3 = 5^5$ Raise both sides to the 5th power

$x^3 = 3125$

$x = \sqrt[3]{3125}$ Apply cube root to both sides

$x = \sqrt[3]{125*25}$

$x = \sqrt[3]{125}*\sqrt[3]{25}$

$x = \sqrt[3]{5^3}*\sqrt[3]{25}$

$x = 5*\sqrt[3]{25}$

$x \approx 14.62009$

4 0

3 years ago

Read 2 more answers

Simplify:

miv72 [106K]

$576 = {2}^{6} \times {3}^{2} \\ \\$
$64 = {2}^{6}$

good luck

6 0

3 years ago

Read 2 more answers

PLEASE HELP DUE IN A HOUR I WILL GIVE BRAINLIST

balandron [24]

Answer: here is an example in the screenshot

it is A,B,C, or D

Step-by-step explanation:

For a given perimeter, the area will be maximized when all the sides are the same length, which makes it actually a square. A square is still a rectangle, though! So, if you know the perimeter, divide it by four to determine the length of each side. Then multiply the length times the width to get the area.

BTW U CAN USE A CALCULATOR

6 0

3 years ago