Answer:
The magazines sold by Jan is 8
<u>Solution:</u>
Let us denote Larry by l, Jan by j and Henry by h.
We are given that Larry sold twice as many magazines as Jan.
So we can formulate an equation as follows;
l =2j --eq1
We also know that Henry sold 8 more magazines than Jan did.
Therefore it can be written as;
h=8+j --eq2
We have also been given that Larry and Henry sold the same amount of magazines.
This can be written as follows;
h = l --eq3
we can rewrite eq1 in term of l
-- eqn 4
By substituting eq4 in eq2 we get;


2h = 16 + l --eq5
From eq3 we know that h = l
Therefore by substituting h for l we can rewrite eq5 as;
2l = 16+l
l = 16
This implies Larry sold 16 magazines.
But we know that Larry sold twice as many magazines as Jan, therefore

j = 8
Hence Jan sold 8 magazines.