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Romashka [77]
3 years ago
10

Emily is entering a bicycle race for charity. Her mother pledges $0.70 for every 0.75 mile she bikes. If Emily bikes 21 miles, h

ow much will her mother donate?
Mathematics
1 answer:
lara [203]3 years ago
6 0
The answer might be 19.60
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If it takes 3,127 feet of computer cable to wire an office building, how much cable will be left if the wire is taken from a 5,0
anyanavicka [17]
This is one of the most complex problems I've seen on Brainly. If you don't understand after reading my lengthy explanation, just tell me.

You have 5000 feet of reel. The office building uses 3127 feet of cable.
So you do 5000-3127 to find the remaining amount of reel.

5000 - 3127 = 1873

Whew! That was quite difficult, wasn't it?
6 0
3 years ago
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Please Help! ddddddddddddddddddd
Westkost [7]

Answer:

-7/12

Step-by-step explanation:

-3/4+1/6

-9/12+2/12

-7/12

6 0
4 years ago
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  Find the value of r, if K is between J and L.  if JK = 6r, KL = 3r, and JL = 27
Ne4ueva [31]
        6r            3r
J_______K_______L
--------------27------------

JK + KL = JL
6r + 3r = 27
9r = 27
r = 27/9
r = 3 <=====

5 0
3 years ago
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Michael has constructed a device that fits on the end of a water hose. With this device, he can adjust the diameter of a tube co
Oduvanchick [21]
 x
---- = 5    (solve for x)
0.6

x = 5(0.6)
x = 3

then....

 3
-----  = 15
0.2

your answer should be 15 ft per second.

hope this helps :)










3 0
4 years ago
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Conservationists tagged 120 ​black-nosed rabbits in a national forest in 1990. In 1991​, they tagged 240 ​black-nosed rabbits in
Sauron [17]

Answer:

Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.

Step-by-step explanation:

Given:

Population for rabbit obeys exponential law.

120 at 1990 and 240 1991 ...after 1 year time period

To Find:

After 9 year  time period how many rabbits will be there.

Solution:

Exponential law goes on present value and various value and time period and defined as ,

let Y be present value Y0 previous year value  and k exponential constant and t be time period.

So

Y=Y0e^(kt)

Here Y=240  ,Y0=120  t=1 year time period

So

240=120e^(k*1)

240/120=e^k

2=e^k

Now taking log on both side, [natural log]

ln(2)=ln(e^k)

ln(2)=kln(e)

k=ln(2)

k=0.6931

For t=9 year of time period

Y0=120,  t=9  ,k=0.6931

Y=Y0e^(k*t)

Y=120*e^(0.6931*9)

=120e^6.2383

=61438.48

=61438 rabbits

8 0
4 years ago
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