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Lapatulllka [165]
3 years ago
7

Can you help me for number 36, please thank you!

Mathematics
1 answer:
EastWind [94]3 years ago
6 0
The slope is 20/13. Yes, the slope is steeper because without the lip on the slide you would travel downward faster.
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Find the area of the shape shown below.
vovangra [49]

Answer:

I believe a=22

Step-by-step explanation:

a=4+4+4+2+8

a=8+4+2+8

a=12+2+8

a=14+8

a=22

8 0
2 years ago
The function and it’s inverse are shown on the same graph. Which statement best describes the relationship between the function
irinina [24]

Can I have the Graph

6 0
2 years ago
Use the remainder Theorem to find the remainder for the given division. (16z^4-1)/(z+1)
Mice21 [21]

Remainder Theorem: when a polynomial <em>P(x) </em>is divided <em>by (x - a), </em>the remainder is <em>P(a).</em>

<em />

Given expression:

\frac{16z^{4}-1}{z+1}

In this case:

P(z)=16z^4-1z=-1

To know the reminder, we have to plug in the value of <em>z </em>in the polynomial:

P(-1)=16(-1)^4-1

Simplifying:

P(-1)=16(1)^{}-1P(-1)=16^{}-1P(-1)=15

Answer: The remainder is 15.

7 0
1 year ago
Betsy bought six bags of rice weighing 30 lbs. total. Which ratio represents the number of bags to lbs?
belka [17]
6/30 or six over thirty 
5 0
3 years ago
What are the missing parts that correctly complete the proof
bonufazy [111]

Answer:

2. \overline{AX}\cong \overline{BX}

3. PX \perp AB - definition of perpendicular

4. \angle PXA \cong \angle PXB - all right angles are congruent

6. \triangle AXP\cong \triangle BXP

7. \overline{PA} \cong \overline{PB}

Step-by-step explanation:

<u>Given: </u>Point P is the perpendicular bisector of AB

<u>Prove: </u>P is equidistant from the endpoints AB

<u>Proof.</u>

1. Point P is on the perpendicular bisector of AB - given

2.\overline{AX}\cong \overline{BX} - definition of bisector

3. PX \perp AB - definition of perpendicular

4.  \angle PXA \cong \angle PXB - all right angles are congruent

5. \overline{PX} \cong \overline{PX} - reflexive property of congruence

6. \triangle AXP\cong \triangle BXP - SAS congruency postulate

7. \overline{PA} \cong \overline{PB} - corresponding parts of congruent triangles are congruent

8. Point P is equidistant from the endpoints of AB - definition of equidistant

5 0
3 years ago
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