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navik [9.2K]
4 years ago
10

Round 8.96278650871 to the nearest millionth.

Mathematics
2 answers:
QveST [7]4 years ago
7 0
The nearest millionth would be 8.962787 since 5 and up means you round up and so the 6 you would round up to a 7
nordsb [41]4 years ago
4 0

Answer:

The answer is 8.96278<u>7</u> .

Step-by-step explanation:

The number above is :

8 = Ones place

8.9 = Tenth place

8.96 = Hundredth place

8.962 = Thousandth place

8.9627 = Ten thousandth place

8.96278 = Hundred thousandth place

8.962786 = Millionth place

8.96278<u>7</u> = Nearest millionth

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What are the roots of f(x) = x2 – 48? –48 and 48 –24 and 24 Negative 8 StartRoot 3 EndRoot and 8 StartRoot 3 EndRoot Negative 4
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Answer:

x=4\sqrt{3},\:x=-4\sqrt{3} are the roots.

Step-by-step explanation:

x=4\sqrt{3},\:x=-4\sqrt{3}

Considering the expression

x^2\:-\:48

Solving

x^2-48=0

x^2-48+48=0+48

x^2=48

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{48},\:x=-\sqrt{48}

Solving

x=\sqrt{48}

  = \sqrt{2^4\cdot \:3}

  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

  = \sqrt{3}\sqrt{2^4}

  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^m}=a^{\frac{m}{n}}

  \sqrt{2^4}=2^{\frac{4}{2}}=2^2

  =2^2\sqrt{3}

  =4\sqrt{3}

So,

x=4\sqrt{3}

Similarly,

x=-\sqrt{48}=-4\sqrt{3}

Therefore, x=4\sqrt{3},\:x=-4\sqrt{3} are the roots.

Keywords: roots, expression

Learn more about roots from brainly.com/question/3731376

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