All categories

3 years ago

How many meters are 345 cm equal to

Mathematics

2 answers:

Sholpan [36]3 years ago

8 0

¿How many m are there in 345 cm?

In 345 cm there are 3.45 m.

Which is the same to say that 345 centimeters is 3.45 meters.

Gwar [14]3 years ago

6 0

There is 100 cm in 1 meter so if thats true then you must take

345/100

and that should be your answer :)

You might be interested in

At a bus station, buses begin their routes at 6 a.M. The schedule for two of the buses is based on the time intervals listed bel

Marianna [84]

Answer:

The next time both will leave the bus station at the same time is 7:15 a.m.

Step-by-step explanation:

Since 15 and 75 are multiples to each other.

So, L.C.M. of 15 and 75 is 75.

So, after 75 minutes both buses will leave the station at the same time.

Also since buses begin their routes at 6 a.m.

So, next time they will meet at

6 hours 0 minutes + 75 minutes = 7 hours 15 minutes = 7:15 a.m.

7 0

3 years ago

7. What is the value of x to the nearest foot? *

Katena32 [7]

The answer is 6713 ft

3 0

2 years ago

(Algebra 2) Find the inverse of f(x) and its domain.

elixir [45]

Let f(x)=y
f^-1(x)=x
y=1/(x+5) - 1
y+1=1/(x+5)
(x+5)=1/(y+1)
x=1/(y+1)-5
f^-1(x)=1/(x+1) -5

denominator cannot equals to zero
x+1≠0
x≠-1

answer
B

4 0

2 years ago

a data set has a mean of 68 and standard deviation of 6. An element in this set is 51. What is z-score for 51? Round your answer

gogolik [260]

z = -2.83

Explanation:

Given:

Mean, μ = 68

Standard deviation, σ = 6

Data point, x = 51

Z score, z = ?

We know:

$z = \frac{data point - mean}{standard deviation} \\\\z = \frac{x - u}{p}$

Substituting the value we get:

$z = \frac{51-68}{6} \\\\z = -2.83$

A negative z score says that the data point is below average.

4 0

3 years ago

The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation

Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

Let X = weights of adult male birds of a certain species

So, X ~ Normal( $\mu=27.5,\sigma^{2} =1.1^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{ X-\mu}{\sigma } }$ ~ N(0,1)

where, $\mu$ = population mean weight = 27.5 grams

$\sigma$ = standard deviation = 1.1 grams

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

Z score = $\frac{ X-\mu}{\sigma } }$ = $\frac{ 29.37-27.5}{1.1 } }$

= 1.7

4 0

2 years ago