All categories

2 years ago

Small dot placed between ones and tenths

Mathematics

2 answers:

MakcuM [25]2 years ago

7 0

That's a decimal point

Marizza181 [45]2 years ago

4 0

That's the "decimal point".

You might be interested in

I will give BRAINLIEST to whoever is correct.

maw [93]

Remember, you can do anything to an equation as long as you do it to both sides

we hates fractions
times both sides by 3
(we could have added 1/3b to both sides but I'm lazy)

4b+6=12-b
add b to both sides
5b+6=12
minus 6 both sides
5b=6
divide both sides by 5
$b=\frac{6}{5}$

8 0

3 years ago

-40-8b=-6(1+7b) what’s the answer

Andre45 [30]

$\text{Hey there!}$

$\mathsf{-40-8b=-6(1+7b)}\\\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}\\\mathsf{-40-8b=-6(1+7b)}$

$\mathsf{Distribute\ the\ RIGHT\ side\ of\ the\ equation }\\\mathsf{Distribute [the\ formula\ is: a(b+c)=a(b)+a(c)=ab+ac]}\\\mathsf{-6(1)+(-6)}(7b)\\\mathsf{-6(1)=-6}\\\mathsf{-6(7b)=-42b}\\\mathsf{\rightarrow\ =-6+(-42b)}$

$\mathsf{-40-8b=-6+(-42b)}\\\mathsf{\rightarrow -8b-40=-42b-6}$

$\mathsf{ADD\ by\ 42b\ on\ your\ sides}\\\mathsf{-8b-40+42b=-42b-6+42b}\\\mathsf{SOLVE\ above\ correct\ to\ get\ us\ to\ the\ next\ step!}\\\mathsf{\rightarrow 34b-40=-6}$

$\mathsf{ADD\ by\ 40\ on\ your\ sides}\\\mathsf{34b-40+40=-6+40}\\\mathsf{Cancel\ out\ -40+40\ because\ that\ gives\ the\ result\ of\ 0}\\\mathsf{-6+40=34}\\\mathsf{\rightarrow New\ equation: 34b = 34}$

$\mathsf{DIVIDE\ both\ of\ your\ sides\ by\ 34}\\\mathsf{\dfrac{34b}{34}=\dfrac{34}{34}}\\\\\mathsf{Cancel\ out: \dfrac{34b}{34}\ because\ that\ gives\ you\ the\ result\ of\ 1b}\\\\\mathsf{Keep:\dfrac{34}{34}\ because\ it\ solves\ for\ b}\\\\\mathsf{\dfrac{34}{34}=34\div34=1}$

$\boxed{\boxed{\boxed{\boxed{\mathsf{Thus\ your\ answer\ is:\boxed{\boxed{\mathsf{b=1}}}}}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

8 0

2 years ago

(2)/(7):0.6x=(4)/(21):0.25

inysia [295]

Answer:

= 1.6

Unless you meant to clarify what in the equation you needed, but that is the answer to it.

7 0

2 years ago

PLEASE HELP ME what is the solution to the system of equations?

masha68 [24]

Times the bottom equation by -4 to cancel out the x’s.
Add the equations.
Solve for y.
Plug in y to find x.

8 0

2 years ago

one x-intercept for a parabola is at the point (-6,0) find the other x-intercept for the parabola defined by this equation y=x^2

Tanya [424]

Hello.

First off, you can factor this equation to find the missing x-intercept.

y = x² + 8x + 12
y = (x + 6)(x + 2)

Then, you can use the zero product property to find the x values.

x + 6 = 0 x + 2 = 0
- 6 - 6 - 2 - 2
x = -6 x = -2

As an ordered pair: (-6, 0) and (-2, 0)

Thus, your answer is x = -6, -2.

6 0

2 years ago