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2 years ago

The price of paper increases by a lot. Book producers respond by supplying ____ books.

Mathematics

1 answer:

lubasha [3.4K]2 years ago

5 0

If the price of paper increases by a lot, then book producers would respond by supplying less books.

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Marsha is changing her phone

Nikitich [7]

month 4: 13.25*4=53. 53+50 = 103

month 4: 25.75*4 = 103

They both cost $103 on month 4

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2 years ago

X-intercept=? y-intercept=? What is the slope?

Nadusha1986 [10]

Answer: x=1 y=-3

just look where the line touches mane

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2 years ago

Please help me I need a lot of help :(

Anna35 [415]

(3 4/7 - 3/5) x 2/3 = 208/105

3/2 x (3 4/7 - 3/5) = 156/35

That is what your two problems are when simplified.
From there on you can tell what is greater then another.

3 0

2 years ago

35. In a simple random sample of 25 high school students, the sample mean of the SAT scores was 1450, and the sample variance wa

Tatiana [17]

Answer:

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

Step-by-step explanation:

Information provided

$\bar X=1450$ represent the sample mean for the SAT scores

$\mu$ population mean (variable of interest)

$s^2 = 900$ represent the sample variance given

n=25 represent the sample size

Solution

The confidence interval for the true mean is given by :

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The sample deviation would be $s=\sqrt{900}= 30$

The degrees of freedom are given by:

$df=n-1=2-25=24$

The Confidence is 0.954 or 95.4%, the value of $\alpha=0.046$ and $\alpha/2 =0.023$ , assuming that we can use the normal distribution in order to find the quantile the critical value would be $z_{\alpha/2} \approx 2.0$

The confidence interval would be

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

3 0

3 years ago

An airplane with an air speed of 165 mph is headed 210°. If the plane encounters a 15 mph wind from the west, find the ground sp

mestny [16]

Since a calculator is involved in finding the answer, it makes sense to me to use a calculator capable of adding vectors.

The airplane's ground speed is 158 mph, and its heading is 205.3°.

_____
A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.

The ground speed and course of the plane are 158 mph @ 205.3°.

4 0

3 years ago