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lozanna [386]
2 years ago
6

The price of paper increases by a lot. Book producers respond by supplying ____ books.

Mathematics
1 answer:
lubasha [3.4K]2 years ago
5 0
If the price of paper increases by a lot, then book producers would respond by supplying less books.
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Which are the side lengths of a right triangle? Check all that apply.
S_A_V [24]

Answer:

3, 14, and sqrt205.

2,9, and sqrt85.

Step-by-step explanation:

Check if they fit the Pythagoras theorem c^2 = a^2 + b^2:

3^2 = 9 , 14^2 = 196.

9 + 196  = 205  which is the square of sqrt205.

So this is a right angled triangle.

6^2 + 11^2 = 36 + 121

= 157 Not right-angled.

19^2 + 180^2  = 32761  Not right-angled.

3^2 + 19^2 = 370    Not right-angled.

2^2 + 9^2 = 85, So this is right angled..

7 1
3 years ago
Read 2 more answers
List the following in order from least (top) to greatest (bottom).<br> 6, 25, 27, V64, 764
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Answer:

6  

25

27

64

764

It's just ascending order, easy.

3 0
2 years ago
Find the result when 40 is increased by 85%
miskamm [114]
47.05 is the anwser. When I used the calculator.
3 0
3 years ago
Find the slope and y-intercept of the line.<br><br> 12x + 2y = –60
Andru [333]
Y = 0 and 12 x = <span>60
</span>12*x+2*y-(-60<span>)=0
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4 0
3 years ago
Indicate the equation of the given line in standard form. The line that is the perpendicular bisector of the segment whose endpo
noname [10]
Well the line that bisects RS, will cut RS in two equal halves, therefore, that line will cut RS perpendicularly at the midpoint of RS.

now, what the dickens is the midpoint of RS anyway?

\bf \textit{middle point of 2 points }\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;R&({{ -1}}\quad ,&{{ 6}})\quad &#10;%  (c,d)&#10;S&({{ 5}}\quad ,&{{ 5}})&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{5-1}{2}~~,~~\cfrac{5+6}{2} \right)\implies \stackrel{midpoint}{\left(2~~,~~\frac{11}{2}  \right)}

so, we know that perpendicular line, will have to go through (2, 11/2)

now, a perpendicular line to RS, will have a negative reciprocal slope to it.  Well, what is the slope of RS anyway?

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ -1}}\quad ,&{{ 6}})\quad &#10;%   (c,d)&#10;&({{ 5}}\quad ,&{{ 5}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5-6}{5-(-1)}\implies \cfrac{5-6}{5+1}\implies -\cfrac{1}{6}

and let's check the reciprocal negative of that,

\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -\cfrac{1}{6}\\\\&#10;slope=-\cfrac{1}{{{ 6}}}\qquad negative\implies  +\cfrac{1}{{{ 6}}}\qquad reciprocal\implies + \cfrac{{{ 6}}}{1}\implies 6

so, then, what's is the equation of a line whose slope is 6, and goes through 2, 11/2?

\bf \begin{array}{lllll}&#10;&x_1&y_1\\&#10;%   (a,b)&#10;&({{ 2}}\quad ,&{{ \frac{11}{2}}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies 6&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\cfrac{11}{2}=6(x-2)&#10;\\\\\\&#10;y-\cfrac{11}{2}=6x-12\implies -6x+y=-12+\cfrac{11}{2}\implies \stackrel{\textit{standard form}}{-6x+y=-\cfrac{13}{2}}
6 0
2 years ago
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