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11Alexandr11 [23.1K]
3 years ago
6

What us 81 percent of 62

Mathematics
2 answers:
Travka [436]3 years ago
5 0
Steps:
1. Do a proportion
X/62= 81/100
2. Do 81 times 62 which is 5,022
3. Now divide 5,022 by 100 which is 50.22
4. Your answer is 50.22
Sergio [31]3 years ago
3 0
62 x .81= 50.22

81% of 62 is 50.22
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A square pyramid has a height of 12 units and a volume of 256 units3. If a square prism has the same the base area and volume as
Juliette [100K]

Answer:

4 units

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3 years ago
A delivery truck weighs 5.5 tons before it is loaded with packages. Once the delivery truck is full of x packages it weighs 6.1
KIM [24]

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2 years ago
A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl
Andrew [12]

Answer: \dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9} or  \dfrac{228}{91885} .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = ^{52}C_9

Now , the combination of 9 cards such that exactly 6 of them are  face cards =  ^{12}C_{6}\times^{40}C_3

Now , the probability that the hand contains exactly 6 face cards will be :-

\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}

=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}

Hence, the probability that the hand contains exactly 6 face cards. is  \dfrac{228}{91885} .

6 0
3 years ago
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