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4 years ago

What us 81 percent of 62

2 answers:

5 0

Steps:
1. Do a proportion
X/62= 81/100
2. Do 81 times 62 which is 5,022
3. Now divide 5,022 by 100 which is 50.22
4. Your answer is 50.22

Sergio [31]4 years ago

3 0

62 x .81= 50.22

81% of 62 is 50.22

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A rectangular water tank carries 40000 litres of water what is the best area if its height is 2 m

Alexus [3.1K]

Answer:

the base area is 20,000

2 x 20,000 = 40,000

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3 years ago

a which family uses about twice the amount of electricity per person than the other two families? Explain your reasoning.

tia_tia [17]

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3 years ago

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At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 18 m

Colt1911 [192]

Answer:

99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 18 minutes

Standard Deviation, σ = 4 minutes

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, 99.7% of the customers have to wait:

$\mu -3\sigma = 18-3(4) = 6\\\mu +3\sigma = 18+3(4) = 30$

Thus, 99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

3 0

3 years ago

A cube-shaped box has a volume of 1/8 of a cubic meter. What is the perimeter of each of its

belka [17]

Given:

The volume of a cube-shaped box is $\dfrac{1}{8}$ cubic meter.

To find:

The perimeter of each of its faces.

Solution:

Let "a" be the side length of the cube shaped box. Then the volume of the box is:

$V=(side)^3$

$V=a^3$

It is given that the volume of a cube-shaped box is $\dfrac{1}{8}$ cubic meter.

$a^3=\dfrac{1}{8}$

Taking cube root on both sides, we get

$a=\dfrac{1}{2}$

Now, the perimeter of each face of a cube is:

$P=4a$

Where, a is the side length of the cube.

Putting $a=\dfrac{1}{2}$ , we get

$P=4\times \dfrac{1}{2}$

$P=2$

Therefore, the perimeter of each face of a cube-shaped box is 2 meters.

5 0

3 years ago

For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12

notsponge [240]

The binomial distribution is given by,
P(X=x) = $(^{n}C_{x})p^{x} q^{n-x}$
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = $(^{100}C_{x})(0.2)^{x} (0.8)^{100-x}$
where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12
∴ P(X≤12) = $(^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1}$ + $(^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3}$ + $(^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5}$ + $(^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7}$ + $(^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9}$ + $(^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11}$ + $(^{100}C_{12})(0.2)^{12} (0.8)^{100-12}$

Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability.

7 0

4 years ago