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Pavel [41]
3 years ago
5

Please help me, I don't understand literally any of this. # 1-6

Mathematics
1 answer:
sergejj [24]3 years ago
3 0
1. y = x
y = 2x - 4

Locate the point of intersection of the 2 graphs. This is the solution set of the graphs, that is: (x, y) = (4, 4).

Solution set: (x, y) = (4, 4)

2. y = -\frac{1}{2}x + 5
y = 3x - 2

Locate the point of intersection of the 2 graphs. This is the solution set of the graphs, that is: (x, y) = (2, 4)

Solution set: (x, y) = (2, 4)

3. y - 2x = 4
y = 2x

Locate the point of intersection of the 2 graphs. The 2 lines are parallel so they do not intersect and therefore no solution set exists for the given set of equations.

Solution set: Does not exist.

4. y - 4x = 8
y = 2(2x +4)

Locate the point of intersection of the 2 graphs. The 2 lines are completely overlapping each other so they intersect intersect at infinite points and therefore infinite solutions exist for the given set of equations.

Solution set: Infinite solutions

5. x + y = 3
y = -3(2x - 1)

Locate the point of intersection of the 2 graphs. This is the solution set of the graphs, that is: (x, y) = (0, 3)

Solution set: (x, y) = (0, 3)

6. -x + y = -2
y = 2

Locate the point of intersection of the 2 graphs. This is the solution set of the graphs, that is: (x, y) = (4, 2)

Solution set: (x, y) = (4, 2)
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Answer: Choice B

2 = \log_{8}(64)

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Explanation:

The original equation is 8^2 = 64 with 8 as the base. That is also the base of the log when we get the final answer shown above. Logs are useful to isolate the exponent.

The general rule is that \text{y} = b^{\text{x}} is equivalent to the log form of \text{x} = \log_{b}(\text{y}) where b is the base of each.

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No

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Definition of a function is: a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output

Here we have more than one output for one input:

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