I think it’s the third one if not I apologize
The surface area of a triangular prism with the 3 sides slant height as 14 the base width as 8 and the base height as 6.9 is 155. 705 in²
<h3>
What is the surface area of a triangular prism?</h3>
The surface area of a triangular pyramid is the total area of all it's faces.
The properties of a triangular prism are;
- It is bounded y three lateral triangular faces meeting at one vertex.
- It has all its faces as triangles
<h3>
How to determine the surface area</h3>
Surface area = Base Area + 1÷2 (perimeter × base height)
But base area = 1÷2 (base side × height)
Base area = 1÷ 2 (8 × 14) = 0.5 × 112 = 56 in²
Perimeter = sum of all the sides = 14 + 8 + 6.9 = 28. 9 in
Base height = 6. 9in
Surface area = 56 + 1 ÷ 2 ( 28.9× 6. 9) = 56 + 0.5 × 199.41 = 56 + 99. 705 = 155. 705 in²
Surface area = 155. 705 in²
Therefore, the surface area of the triangular prism is 155. 705 in²
Learn more about surface area here:
brainly.com/question/16581456
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Answer:
1) True
2) True
3) False
4) True
Step-by-step explanation:
1) You can compare irrational numbers using rational approximations
The above statement is true as given two irrational numbers which can be expressed in decimal format, by rounding up the numbers to a certain number of decimal places, the values of the irrational numbers will be different
2) Square roots can be compared and ordered by comparing and ordering the numbers underneath the radical symbol
The above statement is true as the the values of the numbers under the radical symbol are directly proportional to the square root
3) You cannot compare the value of rational and irrational numbers
The above statement is false because the value of an irrational number can be found between two rational numbers. Therefore, the value of an irrational number is higher than the rational number that precedes it on the left of a number line
4) The closer the numbers being compared, the more decimal places you need to use
The above statement is true as a higher level of detailed value of the numbers being compared will be required given the closeness in value of the numbers being compared.
Answer:
a. 0.9
b. 0.024
c. 0.06
d. 0.2
e. 0.336
Step-by-step explanation:
Since A, B and C are mutually exclusive then P (A U B U C)=P(A)+P(B)+P(C) and P(A∩B∩C)=P(A)*P(B)*P(C).
a.
P (A U B U C)=P(A)+P(B)+P(C)
P (A U B U C)=0.2+0.3+0.4=0.9
b.
P(A∩B∩C)=P(A)*P(B)*P(C)
P(A∩B∩C)=0.2*0.3*0.4=0.024
c.
P(A∩B)=P(A)*P(B)
P(A∩B)=0.2*0.3=0.06
d.
P[(AUB)∩C]=P(AUB)*P(C)
P(AUB)=P(A)+P(B)=0.2+0.3=0.5
P[(AUB)∩C]=0.5*0.4=0.20
e.
P(A')=1-P(A)=1-0.2=0.8
P(B')=1-P(B)=1-0.3=0.7
P(C')=1-P(C)=1-0.4=0.6
P(A'∩B'∩ C')=P(A')*P(B')*P(C')
P(A'∩B'∩ C')=0.8*0.7*0.6=0.336