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2 years ago

In a company there are 33 male and 42 female staff. Calculate the percentage of male and female staffs

Mathematics

1 answer:

VMariaS [17]2 years ago

7 0

Answer: 44%, 56%

Step-by-step explanation:

Given

A company has 33 males and 42 female staff

So, the total staff is the sum of male and female

$\Rightarrow \text{Total=}33+42\\\Rightarrow \text{Total=}75$

The percentage of male staff is

$\Rightarrow \text{Male }\%=\dfrac{33}{75}\times 100\\\\\Rightarrow \text{Male }\%=44\%$

The percentage of female staff is

$\Rightarrow \text{female }\%=\dfrac{42}{75}\times 100\\\\\Rightarrow \text{female }\%=56\%$

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In a race, 27 out of the 50 finished in less than minutes. What percent of swimmers finished the race in less than 57 minutes?

alekssr [168]

Answer:

27 x 2 = 54 = 54% 54% of racers finished in less than 57 minutes

50 x 2 = 100 =

7 0

2 years ago

Read 2 more answers

200 divided by 54 times 15 times 6 equals?

svetoff [14.1K]

200 divided by 54 times 15 times 6 equals 333.3333

3 0

3 years ago

PLS HELP

sertanlavr [38]

Answer:

C. 76 + 7i

Step-by-step explanation:

49 squared is 7 and since it's negative, it is an imaginary number. Therefore, it is 7i. Which leaves C to be the correct option.

8 0

2 years ago

Roberta has $10,540 to invest. She plans to invest her money in certificates of deposit (CDs) that have 2.1% interest, a stock p

ira [324]

Answer:

The amount invested in CDs is $1,340

The amount invested in the stock portafolio is $6,900

The amount invested in the saving accounts is $2,300

Step-by-step explanation:

Let

x ---->the amount invested in CDs at 2.1%

y ---> the amount invested in the stock portfolio at 2.5%

z ---> the amount invested in the savings account at 1.5%

$x+y+z=10,540$ ----> equation A

$z=\frac{1}{3}y$ ----> equation B

substitute equation B in equation A

$x+y+\frac{1}{3}y=10,540$

$x+\frac{4}{3}y=10,540$

$x=10,540-\frac{4}{3}y$ ----> equation C

we know that

The total interest earned by the three amount must be equal to $231.69

$0.021x+0.025y+0.015z=231.69$ ----> equation D

substitute equation B and equation C in equation D

$0.021(10,540-\frac{4}{3}y)+0.025y+0.015(\frac{1}{3}y)=231.69$

solve for y

$221.34-0.0315y+0.025y+0.005y=231.69$

$0.0015y=231.69-221.34$

$0.0015y=10.35$

$y=\$6,900$

Find the value of x

$x=10,540-\frac{4}{3}(6,900)$

$x=\$1,340$

Find the value of z

$z=\frac{1}{3}(6,900)$

$z=\$2,300$

7 0

3 years ago

Hannah scored a total of 170 points on two math tests. The score of the first test was 6 points lower than the second test. How

tester [92]

Ok so in order to do this, you have to set up an equation. Let's make a=the score of the first test and b=the score of the second test. (You can choose different variables, it doesn't matter.) It says the sum of the two equals 170. So, a+b=170. It also says that the score of the first was 6 less than the second. This can be shown as a=b-6. Now you can plug this in for a in your original equation. It will look like:

(b-6)+b=170

You can solve for b.

2b-6=170
2b=176
b=88

Since you want a, plug into either equation for b. I'll use the second one.

a=88-6

So, a=82

8 0

3 years ago