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Rzqust [24]
3 years ago
12

What is the answer to number 7b?

Mathematics
1 answer:
Semmy [17]3 years ago
4 0
Increasing it by 10% will be 11.55. To find teen percent all you do is make it a decimal then multiplying it by 10.50
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A shipping container is in the shape of a right rectangular prism with a length of 1 feet, a width of 9.5 feet, and a height of
Mila [183]

Answer:

11

Step-by-step explanation:

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3 years ago
An art club sells 42 large candles and 56 small candle price of large candle is $10 the cost is $x a small candles cost $5 and c
balandron [24]

Answer:

Profit = $(700 - 42x - 56y)

Step-by-step explanation:

For large candles, the selling price is $10 and its making cost is $x.

So, by selling a large candle the profit is $(10 - x)

Again for small candles, the selling price is $5 and its making cost is $y.

So, by selling a small candle the profit is $(5 - y)

Therefore, in a sell of 42 large candles and 56 small candles the total profit will be, P = 42 (10 - x) + 56 (5 - y)

⇒ P = 420 - 42x + 280 - 56y {Applying distributive property}

⇒ P = $(700 - 42x - 56y) (Answer)

4 0
3 years ago
During peak summer season, a whitewater rafting company
JulsSmile [24]
You have to pay the 90$ we all ready know it’s over 90. 15% of 90 is just 90x0.15 which is 13.50. So the fee (13.50) plus the cost(90) is 103.50$ total for the raft
5 0
2 years ago
g You are planning an opinion study and are considering taking an SRS of either 200 or 600 people. Explain how the sampling dist
Katen [24]

Answer:

By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sampling distribution of size n of a sample proportion p, the mean is p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

Differences between SRS of 200 and of 600

By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.

6 0
3 years ago
Could you guys please help me with this
Illusion [34]
SA = 1,226 in.² (Hope this helps!)
5 0
3 years ago
Read 2 more answers
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