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2 years ago

Plzzzzz HELPPP WITH DIS LOOK AT THE PHOTO

Mathematics

1 answer:

lianna [129]2 years ago

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Vanessa can make 5 portions

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If f(x)=(2x^2)-1, find: -f(3x-1)+2

Sergeeva-Olga [200]

Answer:

-f(3x - 1) + 2 = -18x² + 12x + 1

Step-by-step explanation:

Step 1: Find f(3x - 1)

f(3x - 1) = 2(3x - 1)² - 1

f(3x - 1) = 2(9x² - 6x + 1) - 1

f(3x - 1) = 18x² - 12x + 2 - 1

f(3x - 1) = 18x² - 12x + 1

Step 2: Plug in f(3x - 1)

-(18x² - 12x + 1) + 2

Step 3: Evaluate

-18x² + 12x - 1 + 2

-f(3x - 1) + 2 = -18x² + 12x + 1

8 0

3 years ago

Read 2 more answers

If √6 is the geometric mean between 4 and another number, then the number is 1.5 9 24

konstantin123 [22]

Correct answer is A.

g - geometric mean
$g= \sqrt{ab} 
\\
\\g= \sqrt{6} ,a=4,b=?
\\ \sqrt{6}= \sqrt{4b} 
\\ (\sqrt{6})^2= (\sqrt{4b} )^2
\\6=4b
\\
\\b= \frac{6}{4} = \frac{3}{2}=1.5$

4 0

3 years ago

Need help ASAP Integrated math ll

Solnce55 [7]

Answer:

∠ EFH = 112°

Step-by-step explanation:

∠ ACD and ∠ EFH are Alternate exterior angles and are congruent, thus

11x - 20 = 9x + 4 ( subtract 9x from both sides )

2x - 20 = 4 ( add 20 to both sides )

2x = 24 ( divide both sides by 2 )

x = 12

Thus

∠ EFH = 11x - 20 = 11(12) - 20 = 132 - 20 = 112°

7 0

3 years ago

Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenths place.

luda_lava [24]

Answer:

286.97

Step-by-step explanation:

find the area of the rectangle first

14*15=210

Find the area of a circle

πr^2=a

the radius of the circle is half the height of the rectangle

π*(7*7)=a

a=153.94

Now

Divide the area by two

153.94/2=76.97

Now add the two areas

76.97+210

7 0

3 years ago

Read 2 more answers

The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar

mafiozo [28]

Answer:

$Ratio = \frac{R^2 - r^2 }{ r^2}$

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

$Area = \frac{\theta}{360}\pi r^2$

For the inner circle

$r \to radius$

The sector of the inner circle has the following area

$A_1 = \frac{\theta}{360}\pi r^2$

For the whole circle

$R \to Radius$

The sector of the outer sector has the following area

$A_2 = \frac{\theta}{360}\pi (R^2 - r^2)$

So, the ratio of the outer sector to the inner sector is:

$Ratio = A_2 : A_1$

$Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2$

Cancel out common factor

$Ratio = R^2 - r^2 : r^2$

Express as fraction

$Ratio = \frac{R^2 - r^2 }{ r^2}$

6 0

2 years ago