Question

Which of the following is equivalent to

Answer 1

Answer:

C

Step-by-step explanation:

Using the rules of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$ and

$\sqrt{a}$ × $\sqrt{a}$ = a

Given

$\frac{\sqrt{2a} }{\sqrt{3} }$

Multiply the numerator/ denominator by $\sqrt{3}$

= $\frac{\sqrt{2a} }{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$

= $\frac{\sqrt{2a(3)} }{3}$ = $\frac{\sqrt{6a} }{3}$

Answer 2

Answer:

C

Step-by-step explanation:

Multiply the numerator and denominator by sqrt 3 to rationalize the denominator.

$\frac{\sqrt{2a}}{\sqrt{3}} * \frac{\sqrt{3} }{\sqrt{3} } = \frac{\sqrt{6a} }{3}$