Question

2p^2 -1 =7 Would appreciate some help thank you

Answer 1

For this chaos we must solve the following equation:

$2p ^ 2-1 = 7$

Adding 1 to both sides of the equation we have:

$2p ^ 2 = 7 + 1\\2p ^ 2 = 8$

Dividing by 2 to both sides of the equation:

$p ^ 2 = \frac {8} {2}\\p ^ 2 = 4$

Applying root to both sides:

$p = \pm \sqrt {4}$

Thus, we have two solutions:

$x_ {1} = + 2\\x_ {2} = - 2$

Answer:

$x_ {1} = + 2\\x_ {2} = - 2$

Answer 2

Answer: p = 2

Step-by-step explanation:

To solve this problem, you first have to add 1 to each side of the equation, leaving you with 2p^2 = 8. Then you divide by 2 on both sides leaving you with p^2 = 4. After that, you take the square root of both sides, and because 4 is a perfect square, you get p = 2 as your final answer.