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3 years ago

What is the result of subtracting the second equation from the first? -3x+2y=7 -3x-2y=4

Mathematics

1 answer:

julia-pushkina [17]3 years ago

6 0

The result of subtracting the second equation from the first is $y = \frac{3}{4}$

<u><em>Solution: </em></u>

Given system of equations are:

-3x + 2y = 7 ----- eqn 1

and -3x - 2y = 4 ---- eqn 2

We have to find the result of subtracting the second equation from the first

So we have to subtract second equation from the first

-3x - 2y = 4

-3x + 2y = 7

(-) -----------------

-4y = -3

4y = 3

$y = \frac{3}{4}$

Thus the result of subtracting the second equation from the first is $y = \frac{3}{4}$

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3 years ago

Please help logarithms!

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Given:

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To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

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$\log_34\approx 1.262$

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$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

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