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larisa [96]
3 years ago
8

What is the result of subtracting the second equation from the first? -3x+2y=7 -3x-2y=4

Mathematics
1 answer:
julia-pushkina [17]3 years ago
6 0

The result of subtracting the second equation from the first is y = \frac{3}{4}

<u><em>Solution: </em></u>

Given system of equations are:

-3x + 2y = 7 ----- eqn 1

and -3x - 2y = 4 ---- eqn 2

We have to find the result of subtracting the second equation from the first

So we have to subtract second equation from the first

-3x - 2y = 4

-3x + 2y = 7

(-) -----------------

-4y = -3

4y = 3

y = \frac{3}{4}

Thus the result of subtracting the second equation from the first is y = \frac{3}{4}

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Answer:

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step-by-step explanation:

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3 years ago
A flagpole is at the top of a building. 300 feet from the base of the building, the angle of elevation of the top of the pole is
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Answer: We can use tangent here to find the length of the flagpole

First, find the length of the building + the flag pole

tan 32 = x/300

x=300tan32=187.460805573

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3 years ago
Please help logarithms!
nlexa [21]

Given:

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To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

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