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3 years ago

What is the result of subtracting the second equation from the first? -3x+2y=7 -3x-2y=4

Mathematics

1 answer:

julia-pushkina [17]3 years ago

6 0

The result of subtracting the second equation from the first is $y = \frac{3}{4}$

Solution: 

Given system of equations are:

-3x + 2y = 7 ----- eqn 1

and -3x - 2y = 4 ---- eqn 2

We have to find the result of subtracting the second equation from the first

So we have to subtract second equation from the first

-3x - 2y = 4

-3x + 2y = 7

(-) -----------------

-4y = -3

4y = 3

$y = \frac{3}{4}$

Thus the result of subtracting the second equation from the first is $y = \frac{3}{4}$

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Answer:

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Step-by-step explanation:

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3 years ago

4b+3=−9 i need help it is inportant

Fantom [35]

Answer:

b=-3

Step-by-step explanation:

4b+3=-9

-3 -3

subtract 3 from both sides like so. 3-3 cancels out. -9-3=-12.

4b=-12

youre left with 4b=12 so DIVIDE 4b by 4 and -12 by 4

4b/4=-12/4

4b divided by 4 is 1. -12 divided by 4 is -3

b=-3

plug -3 in for b to make sure its correct

4(-3)+3=-9

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4 years ago

Read 2 more answers

Can you conclude that the figures are congruent? Justify your answers.

Fantom [35]

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4 0

3 years ago

Will give Brainliest

ch4aika [34]

Answer:

B. Quadrilateral PQRS is a trapezoid, because there is one pair of equal slopes, and thus one pair of parallel sides.

Step-by-step explanation:

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The slopes of the sides of quadrilateral PQRS are −23, 78, −23, and 1112.

As we see two of the slopes are same, indicating a pair of parallel sides.

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3 years ago

The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports

german

Answer:

The null and alternative hypothesis are:

$H_0: \mu=5\\\\H_a:\mu< 5$

Test statistic t=-0.256

P-value = 0.4

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that that smartphone carrier's data speeds at airports is less than 5 mbps.

Step-by-step explanation:

The question is incomplete:

Sample mean (M): 4.79

Sample STD (s): 5.8

Sample size (n): 50

This is a hypothesis test for the population mean.

The claim is that that smartphone carrier's data speeds at airports is less than 5 mbps.

Then, the null and alternative hypothesis are:

$H_0: \mu=5\\\\H_a:\mu< 5$

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=4.79.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=5.8.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{5.8}{\sqrt{50}}=0.82$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{4.79-5}{0.82}=\dfrac{-0.21}{0.82}=-0.256$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

This test is a left-tailed test, with 49 degrees of freedom and t=-0.256, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0.4) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that that smartphone carrier's data speeds at airports is less than 5 mbps.

5 0

3 years ago