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Anika [276]
3 years ago
13

If a = 5 in the right triangle what is the value of b and c

Mathematics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

b=5√3, c=10

Step-by-step explanation:

30-60-90 triangle

c=2a

b=a√3

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The car is faster because it’s 120km/hr, wile the train is 75km/hr
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Pamela is 15 years younger than Jiri. The sum of their age is 33. what is Jiris age
Luden [163]

Answer:

24 years

Step-by-step explanation:

let jiri's age be x

Pamela's age=x-15

x+x-15=33

2x-15=33

collect the like terms to similar places

2x=33+15

2x=48

x=24

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3 years ago
Assume there are 3.5 billion Internet users worldwide and 900 million of
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Write out the numbers fully and divide the users in Europe by the total number of people. Multiply by 100 to get it in percentage terms

3 0
2 years ago
A box contains 20 light box of which five or defective it for lightbulbs or pick from the box randomly what's the probability th
Snowcat [4.5K]

Answer:

1

Step-by-step explanation:

Given:-

- The box has n = 20 light-bulbs

- The number of defective bulbs, d = 5

Find:-

what's the probability that at most two of them are defective

Solution:-

- We will pick 2 bulbs randomly from the box. We need to find the probability that at-most 2 bulbs are defective.

- We will define random variable X : The number of defective bulbs picked.

Such that,               P ( X ≤ 2 ) is required!

- We are to make a choice " selection " of no defective light bulb is picked from the 2 bulbs pulled out of the box.

- The number of ways we choose 2 bulbs such that none of them is defective, out of 20 available choose the one that are not defective i.e n = 20 - 5 = 15 and from these pick r = 2:

        X = 0 ,       Number of choices = 15 C r = 15C2 = 105 ways

- The probability of selecting 2 non-defective bulbs:

      P ( X = 0 ) = number of choices with no defective / Total choices

                       = 105 / 20C2 = 105 / 190

                       = 0.5526

- The number of ways we choose 2 bulbs such that one of them is defective, out of 20 available choose the one that are not defective i.e n = 20 - 5 = 15 and from these pick r = 1 and out of defective n = 5 choose r = 1 defective bulb:

        X = 1 ,       Number of choices = 15 C 1 * 5 C 1 = 15*5 = 75 ways

- The probability of selecting 1 defective bulbs:

      P ( X = 1 ) = number of choices with 1 defective / Total choices

                       = 75 / 20C2 = 75 / 190

                       = 0.3947

- The number of ways we choose 2 bulbs such that both of them are defective, out of 5 available defective bulbs choose r = 2 defective.

        X = 2 ,       Number of choices = 5 C 2 = 10 ways

- The probability of selecting 2 defective bulbs:

      P ( X = 2 ) = number of choices with 2 defective / Total choices

                       = 10 / 20C2 = 10 / 190

                       = 0.05263

- Hence,

    P ( X ≤ 2 ) = P ( X =0 ) + P ( X = 1 ) + P (X =2)

                     = 0.5526 + 0.3947 + 0.05263

                     = 1

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%28-5-%28-8%29%29x%5E%7B2%7D%20%2B%28-5-%28-7%29%29x%5E%7B2%7D" id="TexFormula1"
noname [10]

\sqrt{x} (-5-(-8))x^{2} +(-5-(-7))x^{2} = 3.x^{2} \sqrt{x} +2x^{2} = x^{2} (3\sqrt{x} +1)

ok done. Thank to me :>

4 0
2 years ago
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