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xz_007 [3.2K]
3 years ago
15

Without a well-designed, accurate database, executives, managers, and others do not have access to the ____________________ they

need to make good decisions.
Computers and Technology
1 answer:
ohaa [14]3 years ago
6 0

Answer:

Information

Explanation:

Good decisions are normally based on facts which are tangible information that can be analysed to show trends of key figures such as sales, income, production that are so critical in business. A well-designed and accurate database captures and stores these figures in an organised way which will enable the information or data to be analysed to make informed decisions.

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Kevin would like to ensure that his software runs on a platform that is able to expand and contract as needs change. Which one o
Reil [10]

A terminology which best describe Kevin's goal in terms of expansion and contraction as needs change is: A. Scalability.

<h3>What is scalability?</h3>

Scalability can be defined as a measure of the ability of a system to change (expansion or contraction) in performance and cost as a result of changes in demands of application and system processing, especially in a network architecture.

In this context, we can logically deduce that a terminology which best describe Kevin's goal in terms of expansion and contraction as needs change is scalability.

Read more on scalability here: brainly.com/question/14301721

#SPJ1

Complete Question:

Kevin would like to ensure that his software runs on a platform that is able to expand and contract as needs change.  Which one of the following terms best describes his goal? A. Scalability B. Elasticity C. Cost effectiveness D. Agility

8 0
1 year ago
Who developed the Great Compromise ​
Nostrana [21]

Answer:

Roger Sherman

The solution came in the form of a compromise proposed by statesmen Roger Sherman and Oliver Ellsworth of Connecticut. The Great Compromise created two legislative bodies in Congress.

Explanation:

comment how it helps

7 0
3 years ago
What are the ethical implications of online social media after someone has died?
ZanzabumX [31]
<span>Think about the things people might have wanted private, but after death they have no control.</span>
8 0
3 years ago
Double any element's value that is less than controlValue. Ex: If controlValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4
Aleksandr [31]

Answer:

import java.util.Scanner;

public class StudentScores

{

public static void main(String[] args) {

 Scanner scnr = new Scanner(System.in);

 final int NUM_POINTS = 4;

 int[] dataPoints = new int[NUM_POINTS];

 int controlValue;

 int i;

 controlValue = scnr.nextInt();

 for (i = 0; i < dataPoints.length; ++i) {

     dataPoints[i] = scnr.nextInt();

 }

 for (i = 0; i < dataPoints.length; ++i) {

     System.out.print(dataPoints[i] + " ");

 }

 System.out.println();

 for (i = 0; i < dataPoints.length; ++i) {

     if(dataPoints[i] < controlValue){

         dataPoints[i] = dataPoints[i] * 2;          

     }

     System.out.print(dataPoints[i] + " ");

 }

}

}

Explanation:

*Added parts highligted.

After getting the control value and values for the array, you printed them.

Create a for loop that iterates through the dataPoints. Inside the loop, check if a value in dataPoints is smaller than the contorolValue. If it is, multiply that value with 2 and assign it to the dataPoints array. Print the elements of the dataPoints

5 0
3 years ago
Read 2 more answers
A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co
tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

                                                       = (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops                = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

     ∞                             n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

   = 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

6 0
3 years ago
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