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Natali [406]
3 years ago
5

Can someone help me with these questions please, ill give you brainliest.

Mathematics
1 answer:
lesya692 [45]3 years ago
5 0

Problem 9.

Using the Angle Addition Postulate,

m<QRS + m<SRT = m<QRT

Now we replace the measures of the three angles above with the value or expressions we are given, and we solve for x.

2x + 8 + 3x + 14 = 82

5x + 22 = 82

5x = 60

x = 12

m<QRS = 2x + 8 = 2(12) + 8 = 24 + 8 = 32

Answer: 32 degrees

Problem 10.

Using the Angle Addition Postulate,

m<ABC + m<CBD = m<ABD

Now we replace the measures of the two angles above with the values we are given, and solve for the unknown angle.

115 + m<CBD = 180

m<CBD = 180 - 115

m<CBD = 65

Answer: m<CBD = 65 degrees

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2 years ago
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I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
2 years ago
For which equation would x = 8 not be a solution?
Olegator [25]

Answer:

b. 4x = 48

Step-by-step explanation:

If you look closely an multiply 4 x 8, it equals 32, not 48

The other equations:

8 x 8 does equal 64

10 x 8 does equal 80

9 x 8 does equal 72

It's pretty simple once you try each problem first

Hope this helps!

5 0
3 years ago
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