Can someone help me with these questions please, ill give you brainliest.

Mathematics

1 answer:

lesya692 [45]3 years ago

5 0

Problem 9.

Using the Angle Addition Postulate,

m<QRS + m<SRT = m<QRT

Now we replace the measures of the three angles above with the value or expressions we are given, and we solve for x.

2x + 8 + 3x + 14 = 82

5x + 22 = 82

5x = 60

x = 12

m<QRS = 2x + 8 = 2(12) + 8 = 24 + 8 = 32

Answer: 32 degrees

Problem 10.

Using the Angle Addition Postulate,

m<ABC + m<CBD = m<ABD

Now we replace the measures of the two angles above with the values we are given, and solve for the unknown angle.

115 + m<CBD = 180

m<CBD = 180 - 115

m<CBD = 65

Answer: m<CBD = 65 degrees

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Answer and shown work for 5x + y = 10 -x - y = -2

konstantin123 [22]

Solve first equation for y:
5x+y=10
y=10-5x. Plug this equation into second equation

-x-(10-5x)=-2
-x-10+5x=-2
4x=8
x=2 (plug x into first equation)

5(2)+y=10
y=0

4 0

3 years ago

Read 2 more answers

Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se

kolbaska11 [484]

Answer:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

Step-by-step explanation:

Given:

The expression to expand is given as:

$(x-3)(x-9)(x-4)$

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

$(a + b)(c + d) = ac + ad + bc + bd$

$(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27$

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

$(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)$