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lina2011 [118]
3 years ago
9

The sum of three consecutive even integers is 36. Let X represent the first integer X plus to represent the second integer and X

+4 represent a third integer which equation can be used to find the first integer
Mathematics
2 answers:
tatuchka [14]3 years ago
6 0

x,\ x+2,\ x+4-\text{three consecutive even integers}\\\\\text{The equation:}\\\\x+(x+2)+(x+4)=36\\\\3x+6=36\ \ \ \ |-6\\\\3x=30\ \ \ \ |:3\\\\x=10\\x+2=12\\x+4=14

Masja [62]3 years ago
3 0

Answer:

X + X + 2 + X + 4 = 30

Step-by-step explanation:

Here, X represent the first integer,

If the other 2 integers are succeeding even integers,

Then second integer = X + 2,

Third integer = X + 4

Thus, the sum of these integers = X + X + 2 + X + 4

According to the question,

Sum of these integers = 36

X + X + 2 + X + 4 = 30

Which is the required equation that is used to find the first integer.

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Answer:

1.714 feet

Step-by-step explanation:

slope is rise over run.

rise would be the vertical measurement and run would be the horizontal measurement.


24/14 = 12/7


12/7 = 1.714

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2 years ago
(Need asap plz)
Vikentia [17]

Step-by-step explanation:

add up all of the numbers in the five groups then divide the numbers by the number of numbers you have for example if the sum of all of those numbers is let's a 25 and you have 5 numbers you'll divide 25 by 5 and your men will be 5:00 and if the sum of the numbers was 30 and you have six numbers you'll / 30by6 then your answer then the mean will be six

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Step-by-step explanation:

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3 years ago
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Please help! A-level maths.
astra-53 [7]

x+y=k\implies y=k-x

Substitute this into the parabolic equation,

k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0

We're told the line x+y=k intersects C twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

(-7)^2-4(k+3)=49-4(k+3)>0\implies k

We can tell from the quadratic equation that C has its vertex at the point (3, 6). Also, note that

-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5

and

-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6

so the furthest to the right that C extends is the point (5, 2). The line x+y=k passes through this point for 2+5=k\implies k=7. For any value of k, the line x+y=k passes through C either only once, or not at all.

So 7\le k; in set notation,

\{k\mid 7\le k

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3 years ago
Can someone help me please thanks
Nat2105 [25]
With what? I would love to help you
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