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elena55 [62]
3 years ago
5

Mel Company has a net income, before taxes, of $95,000. The treasurer of the company estimates 45 percent of net income will hav

e to be paid for federal and state taxes. The tax for both federal and state is: ...?
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0
Net income before taxes $95,000

Tax for federal and state: 45% * $ 95,000 = 42,750

 
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1 is 25% of what numder
allsm [11]

Answer:

4, it's obvious think of it as a quarter.

Step-by-step explanation:

1 = 25%

2 = 50%

3 = 75%

4 = 100%

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2 years ago
What expression is equivalent to 10-8
Ivahew [28]
There are many expressions equivalent, it just needs the answer to also equal 2.

2×1
3-1
4÷2
1+1

so on
7 0
3 years ago
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A survey of 1,562 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying techn
tester [92]

Answer:

a) We want to test the claim that 35​% of adults have heard of the new electronic reader, then the system of hypothesis are.:  

Null hypothesis:p=0.35  

Alternative hypothesis:p \neq 0.35  

And is a two tailed test

b) z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326  

c) p_v =2*P(z  

d) Null hypothesis:p=0.35  

e) Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

Step-by-step explanation:

Information provided

n=1562 represent the random sample selected

X=522 represent the people who have heard of a new electronic reader

\hat p=\frac{522}{1562}=0.334 estimated proportion of people who have heard of a new electronic reader

p_o=0.35 is the value to verify

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Part a

We want to test the claim that 35​% of adults have heard of the new electronic reader, then the system of hypothesis are.:  

Null hypothesis:p=0.35  

Alternative hypothesis:p \neq 0.35  

And is a two tailed test

Part b

The statistic for this case is given :

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326  

Part c

We can calculate the p value using the laternative hypothesis with the following probability:

p_v =2*P(z  

Part d

The null hypothesis for this case would be:

Null hypothesis:p=0.35  

Part e

The best conclusion for this case would be:

Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

5 0
3 years ago
5n+4=39 find the value of n that makes this equation true
Bond [772]
5n + 4 = 39
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n = 35:5
n = 7
4 0
3 years ago
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Find the solution of this system of equations.
solmaris [256]
X=5+y

Substitute the value of x in second equation
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y= -8



Now let's find the value of x using y

x= 5+y
x= 5 + (-8)
= -3

So,
x= -3
y=-8
3 0
3 years ago
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