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3 years ago

The charge on a charged sphere is concentrated at (or on) it’s

Physics

2 answers:

rewona [7]3 years ago

8 0

The CORRECT answer is:

The charge on a charged sphere is concentrated at (or on) it's SURFACE.

Naily [24]3 years ago

5 0

The charge on a charged sphere is concentrated on its center .

Explanation : 

The charge on a charged sphere is just concentrated in the center of a shell. We can also say that that the charges are being distributed across the charged sphere. This is totally because of the absence of the electric field. In other words, we can say that, inside a conductor, the electric field is zero.

And that is why the charges are distributed across the surface. Due to the electrostatic forces inside the nucleus or the atom, the apparent forces get cancelled and thus the electric field becomes zero.

Read more about Kepler's third rule

brainly.com/question/1086445

#SPJ1

5 0

2 years ago

The electric field in a region of space has the components Ey = Ez = 0 and Ex = (4.00 N/C · m) x. Point A is on the y axis at y

igor_vitrenko [27]

Answer:

$V_{b}-V_{a} = -38.72$

Explanation:

Consider the axis diagram attached.

Given:

Ey = Ez = 0

Eₓ = - 4x N/C · m

Since electric field is in x direction, potential difference would be:

$V_{b} - V_{a} =-\int\limits^{4.40}_{0} {E_{x} } \, dx$

Here we integrate between limits 0 and 4.40 which is distance between A and B along x-axis.

$V_{b} - V_{a} = -4 \left[\begin{array}{ccc}\frac{x^{2} }{2} \end{array}\right]^{4.40}_{0}$

$V_{b}-V_{a} = -4 (9.68)\\V_{b}-V_{a} = -38.72$

5 0

3 years ago

Samantha wants to determine the force she feels in her car as she's going around a corner. What would be some of the assumptions

dalvyx [7]

To determine the Force it is necessary that Samantha starts from the consideration of the dynamic balance between the forces acting on the car. For this, the centripetal force must be equal to the friction force (otherwise the car would lose contact with the ground), the expression of these two forces would be

$F_f = F_c$

$\mu_k mg = \frac{mv^2}{r}$

Here,

$\mu_k$ = Coefficient of kinematic friction

m = mass

g = Acceleration due to gravity

v = Velocity

r = Radius

From this relationship then she should assume the following

1) The car travels at a constant speed

2) There is indeed that frictional force between the car and the road

3) There is no loss of mass during displacement

4) The centripetal force must be equal to the frictional force so that the car does not lose contact or slip

5) The radius must be constant

7 0

3 years ago

A basketball was thrown and reached a velocity of 3 m/s in 0.5 seconds. What was the acceleration of the basketball?

Alborosie

Answer: acceleration is 6 m/s²

Explanation: V = vo + at. If initial speed Is zero,

V = at and a= V/t = 3m/s /0.5 s

6 0

3 years ago

A transformer has a primary voltage of 115 V and a secondary voltage of 24 V. If the number of turns in the primary is 345, how

Eduardwww [97]

Here's a fun and useful factoid:

   The ratio of the voltages on a transformer is the same
   as the ratio of the number of turns in each winding.

So the ratio of (345 to the secondary turns) is (115V to 24V).

That's a proportion.

   (115/24) = (345/x)

I'll bet you can take it and solve it from here.
Just cross-multiply in the proportion and etc. etc.

6 0

3 years ago