A ball is thrown up onto a roof, landing 4 sec later at height of 20m above the release level. The balls path just before landin
1 answer:
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The minimum speed of the water must be 3.4 m/s
Explanation:
There are two forces acting on the water in the pail when it is at the top of its circular motion:
- The force of gravity, mg, acting downward (where m is the mass of the water and g the acceleration of gravity)
- The normal reaction, N also acting downward
Since the water is in circular motion, the net force must be equal to the centripetal force, so:
Where:
v is the speed of the pail
r = 1.2 m is the radius of the circle
The water starts to spill out when the normal reaction of the pail becomes zero:
N = 0
When this occurs, the equation becomes:
And substitutin the values of g and r, we find the minimum speed that the water must have in order not to spill out:
Learn more about circular motion:
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