Answer:
The amount of steel used = 94.38 
Step-by-step explanation:
Height of the tank = 4.5 m.
Diameter of the tank = 4.2 m.
But,
radius = 
= 
radius = 2.1 m
Total surface area of a cylinder = 2
rh + 2
= 2r(r + h)
= 2 x 
x 2.1 (2.1 + 4.5)
= 44 x 0.3 (6.6)
= 87.12
Total surface area of a cylinder = 87.12
Since 
of the steel was wasted, then;
x 87.12 = 7.26
Actual area of steel sheet used = 87.12 + 7.26
= 94.38
Thus, 94.38 of steel was used in making the tank.
Answer:
{-4.6, -4.2, -3.8, -3.4}
Step-by-step explanation:
The length of the space Karlie is dividing is -3-(-5) = 2 units. Then the length of each of those equal 5 spaces will be 2/5 units = 0.4 units.
Each mark on the number line is 0.4 units to the right of the previous one. The first (left-most) mark is 0.4 units to the right of -5, so is at -5+0.4 = -4.6.
The marks have to be placed at -4.6, -4.2, -3.8, and -3.4.
Answer:
The measurement of angle B is 135°
The measurement of angle A is 60°
The measurement of angle C is 75°
Step-by-step explanation:
Angle A is the same value of 60, Angle B is pretty much just 180 - 45, and so is angle C.
Answer:
p = $ 12521.82
Step-by-step explanation:
Interest Rate = 3.6 %, Compounding Frequency: Semi-Annual, Equivalent Annual Interest Rate ![= [1+\frac{0.036}{2}]^(2) - 1 = 0.0363 or 3.63](https://tex.z-dn.net/?f=%3D%20%5B1%2B%5Cfrac%7B0.036%7D%7B2%7D%5D%5E%282%29%20-%201%20%3D%200.0363%20or%203.63)
%
Number of Repayments is 11 with 10 being equal in magnitude and the last one being worth $ 270, the first repayment comes at the end of Year 2
Let $ p be the level payments that required. Therefore,
![100000 = p\times \frac{1}{0.0363} \times [1-\frac{1}{(1.0363)^{10}}] \times \frac{1}{(1.0363)} + \frac{270}{(1.0363)^{12}}](https://tex.z-dn.net/?f=100000%20%3D%20p%5Ctimes%20%20%5Cfrac%7B1%7D%7B0.0363%7D%20%5Ctimes%20%5B1-%5Cfrac%7B1%7D%7B%281.0363%29%5E%7B10%7D%7D%5D%20%5Ctimes%20%5Cfrac%7B1%7D%7B%281.0363%29%7D%20%2B%20%5Cfrac%7B270%7D%7B%281.0363%29%5E%7B12%7D%7D)
100,000 - 176.01 = p x 7.972
p = $ 12521.82
It would be 2.36686390533
