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Mamont248 [21]
3 years ago
14

With regard to mathematics, what is an accepted statement of fact that is used to prove other statements

Mathematics
1 answer:
spayn [35]3 years ago
5 0
In mathematics, a proof is a deductive agruement for a mathematical statement.In the argument,other prevoiusly establised statements, such as theroms, an be used. In principle, a proof can be traced back to self-evident or assumed statements, known as axioms, along with accepted rules of inference.
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A car with a cost price of $5200 is<br> sold at a profit of 15%. Calculate the<br> selling price
andriy [413]

Answer:

We are given the initial price of a car and we are also told that the car sold for a 15% profit which means that the price that the car was sold for is 15% more than it's initial price.  This is just a simple multiplication problem which we multiply the initial price by the total percentage plus 0.15

Sold\ Price = Initial\ Price *(Total\ Percentage+Profit\ Percentage)

Sold\ Price = \$5200*(1+0.15)

Sold\ Price = \$5200*(1.15)

Sold\ Price = \$5980

Therefore, our final answer is that the selling price was $5980

<u><em>Hope this helps! </em></u>

5 0
2 years ago
Coefficient of y^15x^2 in expansion of (y^3+x)^7
Hitman42 [59]
The coefficient of y∧15×∧2 in expansion of (y∧3+x)∧7 is (15×2)+(3×7)= 51
7 0
3 years ago
Read 2 more answers
8TH GRADE MATH HELP PLEASE
s2008m [1.1K]

Answer:

55 is the answer hope it helps...

6 0
2 years ago
Read 2 more answers
Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.
igor_vitrenko [27]

Answer:

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7

So, the solution of the equation is

y = Ae^{m_{1} t} + Be^{m_{2} t}

where m₁ = 3 and m₂ = -7.

So,

y = Ae^{3t} + Be^{-7t}

Also,

y' = 3Ae^{3t} - 7e^{-7t}

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1      (1)

y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}

Substituting A into (1) above, we have

\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1      \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}

Substituting B into A, we have

A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}

Substituting A and B into y, we have

y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

So the solution to the differential equation is

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

6 0
3 years ago
If at a toy store, 2 board games cost $13.40, what is the unit price of a board game?
olganol [36]

Answer:

The unit price of a board game is $6.70

Step-by-step explanation:

1 board/2boards = x/13.4

Cross multiply:

13.4*1/2x

13.4/2x

x=6.7

Hope this helps plz hit the crown :D

7 0
2 years ago
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