Here speed of first train is slower than speed of second train. So if they catch up , the distance traveled will be same since they left the same station at different times.
But the time traveled will be different .
Let us say the two trains meet at time t ,
Distance = speed * time
Distance traveled by first train = 40 t
Since second train is leaving after three hours , so
Distance traveled by second train = 60(t-3)
As discussed earlier, distance traveled will be same, so

distributing 60 over t-3




t=9
So the second train will meet the first at 9 p.m.
Answer:
6 mi
Step-by-step explanation:
I think so it 6mi I need help
Answer:
9
Step-by-step explanation:
PEMDAS
6 + (3^3) ÷ 9
6 + [(27) ÷ 9]
6 + [ 3 ]
= 9
Answer:
what is the question I didn't get it please explain what we have to find
Step-by-step explanation:
Area=228 feet sqa.
Length=12 ft.
Breadth=(228/12) ft.
=19 ft.
Perimeter=2(12+19) ft.
=2×31 ft.
=62 ft.
HOPE IT HELPS UH!!☺️☺️