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4 years ago

With regard to mathematics, what is an accepted statement of fact that is used to prove other statements

1 answer:

5 0

In mathematics, a proof is a deductive agruement for a mathematical statement.In the argument,other prevoiusly establised statements, such as theroms, an be used. In principle, a proof can be traced back to self-evident or assumed statements, known as axioms, along with accepted rules of inference.

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the length of a rectangle is 10 ft more than the width. if the perimeter is 64 feet then what is the length of the rectangle in

Maru [420]

Answer:

use area to solve it

Step-by-step explanation:

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3 years ago

-2 + (-6y) + 5 y - 8y y=4<br> PLEASE ANSWER ASAP AND SHOW ME HOW YOU GOT IT!!!!

mr Goodwill [35]

Answer:

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3 years ago

Mr. Anders and Ms. Rich each drove from a business meeting. Mr. Anders traveled east at 100 kilometers per hour and Ms. Rich tra

adelina 88 [10]

If you counted up until they were 100 kilometers apart it would look like this:
Mr. A - 100, 200, 300, 400, 500
Ms. R - 80, 160, 240, 320, 400

They were 100 kilometers apart in 5 hours.

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3 years ago

Sam can give 4 dogs a bath in 3/4 hours.How many dongs can Sam wash in 1 hour?

lisabon 2012 [21]

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7 0

4 years ago

Each of the sides of a pentagon is 12 cm long. Two ants are walking from point A to point D along the sides of the pentagon. One

AVprozaik [17]

Answer:

The average speed of the second ant is 2 cm/s

Step-by-step explanation:

The details of the ants moving on the sides of the pentagon are;

The length of the sides of the pentagon = 12 cm

The path of the first ant = A to B, B to C, then C to D

The average speed of the first ant = 3 cm/s

The path of the second ant = A to E, and E to D

The time of arrival of the second ant at the point D = The time of arrival of the first ant at the point D

Given that both ants departed at the same time, from point A, we have;

The time it takes the first ant to arrive at the point D = The time it took the second ant to arrive at the point D

The distance from A to B = 12 cm

The distance from B to C = 12 cm

The distance from C to D = 12 cm

∴ The distance traveled by the first ant from A to D = 12 cm + 12 cm 12 cm = 36 cm

Average speed = (Total distance)/(Total Time)

Total time = (Total distance)/(Average speed)

Let 't' represent the time it takes the first ant to move from point A to point D, we have;

t = 36 cm/(3 cm/s) = 12 seconds

Therefore, the time it takes the first ant to move from point A to point D, t = 12 seconds = The time it takes the second ant to move from point A to point D through point E

The total distance traveled by the second ant from A to point E, then from point E to point D, $T_{d2}$ = 12 cm + 12 cm = 24 cm

The average speed of the second ant, v₂ = $T_{d2}$ /t

∴ v₂ = 24 cm/(12 seconds) = 2 cm/s

The average speed of the second ant, v₂ = 2 cm/s.

8 0

3 years ago