<h2>Length = 11</h2><h2>Width = 6</h2>
The area of a rectangle is 66 ft^2:
L * W = 66
Length of the rectangle is 7 feet less than three times the width:
L = 3W-7
Substitute L in terms of W:
(3W-7) * W = 66
Factorise the equation:
3W^2 -7W = 66
3W^2 - 7W - 66 = 0
Factors of 66 =
1 66, 2 33, 3 22, 6 11
(3W + 11) (W - 6) = 0
Solve for W:
3W + 11 = 0
3W = 11
W = 3/11
W - 6 = 0
W = 0 + 6
W = 6
Using the original equation, find L:
L = 3W-7
L = 3(6)-7
L = 18-7
L = 11
L * W = 66
11 * 6 = 66
I don’t know the answer sorry
2.2 times 3.3=7.26 because u just do it normally and move the decimal in twice because it's in two place values and there are 2 decimals so u move it twice to the left
A) -9
-7(x+9)=9(x-5)-14x
-7x-63=9x-45-14x
-45 -45
-7x-18=9x-14x
+7x +7x
-18=9x+7x-14x
-18=2x
(-18)/2=(2x)/2
-9=x
Answer:
OS is congruent to SQ
Step-by-step explanation:
