The shape has sixty sides
working out:
180 - 174 = 6
360 / 6 = 60
2. 2.70&20.70
3. 9.45&31.95
4. 25.31&59.00
5. 24.75&99.74
6. 48.60&97.20
7. 231.25&416.25
Given:
A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.
To find:
The surface area of the pyramid to the nearest whole number.
Solution:
A square base pyramid contains square base with edge 10 in. and 4 congruent triangles with base 10 in. and height 4 in.
Area of a square is



So, area of square base is 100 sq. in.
Area of a triangle is



So, area of each triangular surface is 20 sq. in.
Now, the total surface area of the pyramid is
Total area = Area of square base + Area of 4 congruent triangles.




Therefore, the area of the pyramid is 180 sq. in.
Answer:
30 i think
Step-by-step explanation:
Answer:
The length of the slant height of the square pyramid is 20 in.
Step-by-step explanation:
The lateral surface area of a regular pyramid is the sum of the areas of its lateral faces.
The general formula for the lateral surface area of a regular pyramid is

where
represents the perimeter of the base and
the slant height.
From the information given we know that:
- The lateral surface area of a square pyramid is 440 in².
- The area of the base is 121 in².
And we want to find the the slant height of the pyramid.
For this, we also need to know that the area of a square is given by
, where <em>s</em> is the length of any side and the perimeter of a square is given by
.
Applying the formula for the area of a square we can find the length of the side

The perimeter of the base is

Next, we can apply the formula for the lateral surface area and solve for
the slant height.

The length of the slant height of the square pyramid is 20 in.