Question

You also learn in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text (without formatting). A typical book has about 400 pages. How many such books can a 9-gig flash drive hold? _______________

Answer 1

Answer:

The flashdrive can hold 35389 400-pages-books

Explanation:

If $\frac{2}{3}$ of a page occupies 1 kB of memory, we can calculate how much memory a book will take

$2/3kB=1 page\\ x kB=400 pages\\266.67 kB=400 pages$

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.

To do the calculation, we have to know how many kilobytes are in 9 gigabytes.

There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

$Memory_{in _kilobytes}^{} =1024\frac{kilobytes}{megabytes} *1024\frac{megabytes}{gigabytes}*9=9437184 kilobytes$

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

$Books=\frac{Flash drive memory}{Filesize of a book} =\frac{9437184kilobytes}{266.67\frac{kilobytes}{book} } =35389,4 books$

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.