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Alexxandr [17]
3 years ago
11

5/8 + 3/8 simplified

Mathematics
2 answers:
noname [10]3 years ago
7 0
8/8 = 1 is the answer
shtirl [24]3 years ago
5 0

you add them together to get 8/8 and that simplifies to 1

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Suppose p(a) = 0.40 and p(a 
sveticcg [70]
Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

P(A\cup B)+P(A\cap B)=P(A)+P(B)


For parts (a) and (b), you're given everything you need to determine P(B).

For part (c), if A and B are mutually exclusive, then P(A\cap B)=0, so P(A\cup B)=P(A)+P(B). If the given probability is P(A\cup B)=0.55, then you can find P(B)=0.15. But if this given probability is for the intersection, finding P(B) is impossible.


For part (d), if A and B are independent, then P(A\cap B)=P(A)\cdot P(B).
8 0
3 years ago
Circle A has a diameter of approximately 20 inches and an area of approximately 300 in2.
Katena32 [7]

Answer:

4. About 2,700 in2

Step-by-step explanation:

The area of a circle (A), measured in square inches, is directly proportional to the square of its diameter (d), measured in inches. That is:

A \propto d^{2}

A = k\cdot d^{2}

Where k is the constant of proportionality, dimensionless.

In consequence, the following relationship between circles A and B is obtained:

\frac{A_{B}}{A_{A}} = \frac{d_{B}^{2}}{d_{A}^{2}}

The area of the circle B is now cleared:

A_{B} =\left(\frac{d_{B}}{d_{A}} \right)^{2}\cdot A_{A}

Given that d_{A} = 20\,in, d_{B} = 60\,in and A_{A} = 300\,in^{2}, then:

A_{B} = \left(\frac{60\,in}{20\,in} \right)^{2}\cdot (300\,in^{2})

A_{B} = 2700\,in^{2}

Therefore, the correct answer is 4.

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Is there a picture or is it just that
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