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lesya692 [45]
3 years ago
7

Look at the data points on the graph Is this relationship a function?

Mathematics
2 answers:
Tcecarenko [31]3 years ago
7 0
It issssssssssssssssss 1,1
Karolina [17]3 years ago
6 0
No, usint the vertical line test, the dots on 2A and 2B will line up with each other, proving it isnt a function.
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Rename the number to 120,000 ten thousand
Ray Of Light [21]
120,000 renamed to ten thousand (10,000) is twelve ten thousand. Ten thousand in number form is 10,000.  When you divide 120,000 (one hundred and twenty thousand)  by 10,000 (ten thousand) you get 12.  120,000 (one hundred and twenty thousand)  /10,000 (ten thousand) = 12. So there are twelve ten thousands in 120,000.
4 0
3 years ago
Find the surface area of a rectangular prism with base 4 m by 5 m and height 8 m.
Andre45 [30]

Answer:

Step-by-step explanation:

surface area=area of sides +area of top and bottom

=2(4+5)×8+2×(4×5)

=2[(9×8)+20]

=2[72+20]

=2×92

=184 m²

4 0
3 years ago
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Which relation is a function?
Degger [83]

Answer: Id say C.

Step-by-step explanation: The other two can't possibly be a function.

<h2><em>Mark as brainliest if im correct please</em></h2>

5 0
3 years ago
Find the right quotient. 36m 5 n 5 ÷ (12m 3)
polet [3.4K]
ANSWER

The right quotient is

3  {m}^{2} {n}^{5}

EXPLANATION


The given expression is :

\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  \frac{36}{12}  \times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3\times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


Recall that,


\frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n}
We apply this property to obtain;



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3 \times   {m}^{5 - 3}  \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3  {m}^{2} {n}^{5}

5 0
3 years ago
Read 2 more answers
Math question quadratics
denpristay [2]

Answer: The length and width are 50 and 30 meters (or 30 and 50 meters).

Step-by-step explanation:

To solve this question, we can represent variables for the length and width in two equations.

2l + 2w = 160\\\\l * w= 1500

To solve for one of the variables, you'll have to substitute one of the variables, so solve for one of them:

2l = 160 - 2w\\l = 80 - w

(80-w)*w=1500\\\\-w^2 + 80w - 1500 = 0\\\\w^2 - 80w + 1500 = 0

Now, we have a standard quadratic equation that we can factor. When factoring, you'll get this:

(w-50)(w-30) = 0

This tells us that the width could be either 50 or 30.

Substitute 50 into one of the equations to find the length:

2 (l) + 100 = 160

l = 30.

The length and width are 50 and 30 meters (or 30 and 50 meters).

4 0
3 years ago
Read 2 more answers
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