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3 years ago

7

What is 2x times x to the second power

1 answer:

Drupady [299]3 years ago

4 0

The correct answer is 2x^3
Hope this helped :)

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PLEASE HELP!!!!<br><br><br> Thanks, Anyone who answers I appreciate it very much!!

Ivan

Answer:

Linear Decreasing

Step-by-step explanation:

Exponential graphs are curved, but this line is straight, so it's linear. It's decreasing since the graph moves from left to right, and as you can see, the line starts from the left tall but gradually goes lower as it goes towards the right.

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3 years ago

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Point C is reflected across the y-axis. Which point represents the reflection? ANWSER QUICKLY PLEASE!

sp2606 [1]

Answer:

whichever is the same on the y cordanate but not the x cordanate (opsite side of 0)

Step-by-step explanation:

Change the negativity of the first number in the cords are pair then chose that answer that is there

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3 years ago

Delta Math! Please help.

vodka [1.7K]

Answer:

x = 1.5 $\sqrt{3}$

Step-by-step explanation:

using the sine ratio in the right triangle and the exact value

sin60° = $\frac{\sqrt{3} }{2}$ , then

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{x}{3}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2x = 3 $\sqrt{3}$ ( divide both sides by 2 )

x = 1.5 $\sqrt{3}$

6 0

2 years ago

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HELPP!!what is the answer to this picture above^

nasty-shy [4]

Answer:

$\fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}$

${ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}$

Step-by-step explanation:

$\star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}$

$\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}$

$\underline{ \underline{ \tt{Finding \: the \: distance}}}$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{144 + 81}}}$

$\mapsto{ \sf{Distance = \sqrt{225} }}$

$\mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}$

$\mapsto{ \boxed{\sf{Distance = 15 \: units}}}$

$\underline{ \underline {\tt{Finding \: the \: Midpoint}}}$

$\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}$

$\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

3 0

3 years ago

(2x-8)(2x+9) help please

lesya [120]

$(2x - 8)(2x + 9) \\ 4 {x}^{2} + 18x - 16x - 72 \\ 4 {x}^{2} + 2x - 72$

HOPE IT HELPS

PLEASE GIVE BRAINLIEST

4 0

3 years ago

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