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Elza [17]
3 years ago
13

Consider three stock funds, which we will call Stock Funds 1, 2, and 3. Suppose that Stock Fund 1 has a mean yearly return of 8.

00 percent with a standard deviation of 16.30 percent; Stock Fund 2 has a mean yearly return of 11.40 percent with a standard deviation of 18.80 percent, and Stock Fund 3 has a mean yearly return of 13.10 percent with a standard deviation of 8.90 percent. (a) For each fund, find an interval in which you would expect 95.44 percent of all yearly returns to fall. Assume returns are normally distributed. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.) Fund 1: [ 8.00 , 16.30 ] Fund 2: [ 11.40 , 18.80 ] Fund 3: [ 13.10 , 8.90 ] (b) Using the intervals you computed in part a, compare the three funds with respect to average yearly returns and with respect to variability of returns. Fund 1 has the average and the variability. Fund 2 has the average and the variability. Fund 3 has the average return and the variability. (c) Calculate the coefficient of variation for each fund, and use your results to compare the funds with respect to risk. Which fund is riskiest

Mathematics
1 answer:
shtirl [24]3 years ago
3 0

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

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An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ
Tema [17]

Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558

b) The approximate probability that at least 9 carry the gene is:

P(x\geq9)=1-P(x\leq 8)\\\\\\

P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\

P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021

8 0
3 years ago
What term is used to describe a systematic repayment of a loan through a set number of payments at a specific rate?
Elden [556K]

Answer:

Credit

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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agasfer [191]

Answer:

Step-by-step explanation:

A, B and C must be real numbers, and A and B are not both zero (which would cause division by zero in the calculation of the slope).

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3 years ago
The sum of half a number and two-thirds of the number is less than 14
Gre4nikov [31]
Suppose the number is y >>>>>So y/2 +2y/3 <14 
multiply both sides by 6>>>>>>>>>. 6y/2 +6x2y/3 <14x6
3y + 4y < 84
7y         <84
y           <84/7
y           < 12
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3 years ago
Find the length of AE in the diagram shown.
likoan [24]
The answer would be 7.5, since 6/9=2/3 and 5/7.5=2/3, then the sides are equal ratios.
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