Answer:
Explanation:
998 - 977 = 21 peaks /minute or about every 2.86 seconds
Answer:
The distance travel in its lifetime of earth is
![x=1.7595m](https://tex.z-dn.net/?f=x%3D1.7595m)
Explanation:
Change respecto the pion
The speed of the pion:
Knowing the speed of the light is about
![v_l=3x10^{8}](https://tex.z-dn.net/?f=v_l%3D3x10%5E%7B8%7D)
![v_p=3x10^{8}*0.23c=69x10^6](https://tex.z-dn.net/?f=v_p%3D3x10%5E%7B8%7D%2A0.23c%3D69x10%5E6)
Now to determinate the distance
![v=\frac{x}{t_p}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bx%7D%7Bt_p%7D)
![x=v*t=69x10^6m/s*2.55x10^{-8}s](https://tex.z-dn.net/?f=x%3Dv%2At%3D69x10%5E6m%2Fs%2A2.55x10%5E%7B-8%7Ds)
![x=1.7595m](https://tex.z-dn.net/?f=x%3D1.7595m)
1. Stop transmitting start and stop sending photons. This is typical morse code like transmissions of information. By varying the pattern of starts stops you vary the information sent. Also used in digital communications over radios, modems, and pulse dialing over radio/phones.
<span>2. Change the frequency. You use a pattern of shorter and longer wavelengths of radio waves higher and lower energies of individual photons to transmit information. This is frequency modulation </span>
Question:
A. Engineer A: "When the sample alpha decays, it will give off alpha particles. These will
trigger a photosensor (a device that senses forms of light) that will open the lock."
B. Engineer B: "When the sample alpha decays, it only releases large amounts of heat.
This will trigger a thermometer that will open the lock."
C. Engineer C: "When the sample alpha decays, it will lose mass, This will trigger a scale
that will open the lock."
D. Engineer D: "When the sample alpha decays, it will give off negatively charged alpha
particles. Because alpha particles are electrons, they will complete a circuit that will
open the lock."
Answer:
The correct option is;
A. Engineer A: "When the sample alpha decays, it will give off alpha particles. These will trigger a photosensor ( a device that senses forms of light) that will open the lock"
Explanation:
Here, we note that in alpha decay (α-decay) there is an emission of an alpha particle or helium nucleus with the transformation of the parent element nucleus into that of a different element, having reduced mass and atomic numbers
Alpha particles are a form of ionizing radiation with a mass of 6.64 × 10⁻²⁷ kg and therefore they can be sensed by a photo sensor but will be slowly sensed by a scale.
If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positive number in meters, will the bullet hit if aimed directly at a target 180 m away
The muzzle velocity of the bullet is 275 m/s
Answer:
y = -1.1109 m
Explanation:
Range = ![\frac{v^2sin2\theta}{g}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E2sin2%5Ctheta%7D%7Bg%7D)
range = 85 m
velocity = 275 m/s
g = 9.8 m/s²
![85 = \frac{(275)^2sin2 \theta}{9.8}](https://tex.z-dn.net/?f=85%20%3D%20%5Cfrac%7B%28275%29%5E2sin2%20%5Ctheta%7D%7B9.8%7D)
![833=(275)^2sin2\theta](https://tex.z-dn.net/?f=833%3D%28275%29%5E2sin2%5Ctheta)
![833= 75625sin2\theta](https://tex.z-dn.net/?f=833%3D%2075625sin2%5Ctheta)
![0.01101 =sin2 \theta](https://tex.z-dn.net/?f=0.01101%20%3Dsin2%20%5Ctheta)
![0.005505 =sin \theta](https://tex.z-dn.net/?f=0.005505%20%3Dsin%20%5Ctheta)
![\theta =sin^{-1}(0.005505)](https://tex.z-dn.net/?f=%5Ctheta%20%3Dsin%5E%7B-1%7D%280.005505%29)
![\theta = 0.3154^0](https://tex.z-dn.net/?f=%5Ctheta%20%3D%200.3154%5E0)
If the bullet is aimed at a target 180 m, time required to travel 180 m with horizontal component will be;
![t=\frac{180}{275cos0.3154}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B180%7D%7B275cos0.3154%7D)
t = 0.6546 sec
To determine, how low as a positive number in meters.
![y=vyt-\frac{gt^2}{2}](https://tex.z-dn.net/?f=y%3Dvyt-%5Cfrac%7Bgt%5E2%7D%7B2%7D)
y =
![\frac{9.8*(0.6546)^2}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B9.8%2A%280.6546%29%5E2%7D%7B2%7D)
y = 0.9909 - 2.1018
y = -1.1109 m