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Ghella [55]
3 years ago
6

During a tug-of-war, team A pulls on team B by applying a force of 1390 N to the rope between them. How much work does team A do

if they pull team B toward them a distance of 3.68 m
Physics
1 answer:
butalik [34]3 years ago
7 0

Answer:

5115.2 J

Explanation:

Work: This can be defined as product of force and distance. The S.I unit of work is Joules (J).

From the question,

The expression for work is given as

W = F×d................. Equation 1

Where W = Work done by team A, F = Force applied by team A, d = distance moved by team B.

Given: F = 1390 N, d = 3.68 m

Substitute into equation 1

W = 1390×3.68

W = 5115.2 J.

Hence the work done by team A in pulling team B = 5115.2 J

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Marina CMI [18]

Answer:

n = 4.35 x 10¹⁹          

Explanation:

Given that

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I=3.48  A

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I = 6.96 A

We know that

Charge = Current x time

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q= 6.96 C

The charge on electron ,e= 1.6 x 10⁻¹⁹

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n=\dfrac{q}{e}

n=\dfrac{6.96}{1.6\times 10^{-19}}

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5 0
4 years ago
Carbon is allowed to diffuse through a steel plate 15 mm thick. The concentrations of carbon at the two faces are 0.65 and 0.30
beks73 [17]

Answer:

T=575.16K

Explanation:

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D is the diffusion coefficient, where,

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J=-(D_0 exp(\frac{-Q_D}{RT}))\frac{\Delta }{\Delta x}

clearing T,

T=\frac{Q_d}{R*ln(\frac{J*\Delta x}{D_0*\Delta C})}

Replacing our values

T=-\frac{80000}{8.31*ln(\frac{(6.2*10^{-7})(-15*10^{-3})}{(1.43*10^{-9})(0.65-0.30)})}

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4 0
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v₁ = 1.626991...

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