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Ghella [55]
3 years ago
6

During a tug-of-war, team A pulls on team B by applying a force of 1390 N to the rope between them. How much work does team A do

if they pull team B toward them a distance of 3.68 m
Physics
1 answer:
butalik [34]3 years ago
7 0

Answer:

5115.2 J

Explanation:

Work: This can be defined as product of force and distance. The S.I unit of work is Joules (J).

From the question,

The expression for work is given as

W = F×d................. Equation 1

Where W = Work done by team A, F = Force applied by team A, d = distance moved by team B.

Given: F = 1390 N, d = 3.68 m

Substitute into equation 1

W = 1390×3.68

W = 5115.2 J.

Hence the work done by team A in pulling team B = 5115.2 J

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From the question we are told that

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         I  =  \frac{ c *  B^2  }{ 2 * \mu_o  }

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          B  =  \sqrt{ \frac{ 2 *  4\pi *10^{-7} *   0.0215  }{ 3.0*10^{8}} }

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substituting values

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substituting values          

       w =  2 *  3.142   *  \frac{3.0*10^{8}}{ 6.90 }  

        w =  2.732 *10^{8} rad  \ s^{-1}  

Generally the induced emf is mathematically represented as

        \epsilon  =  N *  B  *  A  *  w * sin (wt )

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substituting values

         \epsilon  = 1  *    1.342 *10^{-8}   *  0.0284  *2.732 *10^{8}  

         \epsilon  = 0.1041 \  V  

         

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