Which planet has a rotational period closest to that of Earth?
1 answer:
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Let's see what variables we've got first. Hmmm. We have:
Displacement, d = 28 m
Time taken, t = 11 s
Initial velocity, u = 0 m/s (at rest)
And now we need to find the final velocity, v. Among the 4 (or 5) equations of motions, there's no equation that will let us simply plug in the values and give an answer sigh. But fear not! We'll do it in steps.
I'm going to pick one of the motion equation to find more information:
I know everything except for a in this one, so I I'll use this! After plugging in values, I get a = 0.4628 m/s^2.
Now I'm going to use another motion equation that has v in it because that needs to be solved!
Now I know everything except dial velocity v. Nice!
v = 0 + (0.4628)(11)
Displacement, d = 28 m
Time taken, t = 11 s
Initial velocity, u = 0 m/s (at rest)
And now we need to find the final velocity, v. Among the 4 (or 5) equations of motions, there's no equation that will let us simply plug in the values and give an answer sigh. But fear not! We'll do it in steps.
I'm going to pick one of the motion equation to find more information:
I know everything except for a in this one, so I I'll use this! After plugging in values, I get a = 0.4628 m/s^2.
Now I'm going to use another motion equation that has v in it because that needs to be solved!
Now I know everything except dial velocity v. Nice!
v = 0 + (0.4628)(11)
Answer:
3. Her angular speed increases because her angular momentum is the same but her moment of inertia decreases
Explanation:
II ωi the intial angular momentum of the skater. Her angular momentum changes to If ωf after pulling her arms in.
It must be noted that If is less than II, then it is because her arms now go round not far from the rotation axis which brings down the mementos of inertia.
Angular momentum does not change since torque is O.
Note: the mathematical representations are better written on the attached diagram.
