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miskamm [114]
3 years ago
6

Define mechanical energy. Using the example of the skateboarder on the half-pipe, explain how kinetic and potential energy relat

e to the mechanical energy at different positions. Enter your answer in the space provided.
Chemistry
1 answer:
nataly862011 [7]3 years ago
4 0
Mechanical energy is an energy that needs a medium to travel. Kinetic energy relates to the skateboarder as he moves across the pipe, and potential relates to right before he leaps onto the pipe with his skateboard.
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19. When an atom of iron loses all of its 4s electrons and one of its 3d electrons, what is its charge?
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Its charge would be the amount of electrons that are lost in total, which the information is not stated

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4 years ago
Carefully looking at an object or process
densk [106]
<span>observation

They utilize and make use of the scientific method in order to have clear basis and evidence for their investigations. Research method is always used to answer every scientific inquiry and in gaining evidential data or knowledge. The scientific method has the following process or at least undergoes the process of
1. Observation</span> 
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4 0
3 years ago
Looking at the pressure values, at which point would you see a high<br> pressure system?
Tamiku [17]

Answer:

B

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6 0
3 years ago
What is required for electricity to flow? Explain.
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6 0
4 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction: P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH
Pie

Answer: -1835 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H_1=+157kJ (1)

P_4(g)+6Cl_2\rightarrow 4PCl_3(g)  \Delta H_2=-1207J (2)

Net chemical equation:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H=? (3)

Multiplying equation (1) by 4,  and reversing we get

4PCl_3(g)+4Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_4=4\times -157kJ=-628kJ (4)

Adding (2) and (4)

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_3=\Delta H_2+\Delta H_4=-1207kJ-628kJ=-1835kJ  

Thus enthaply change for the reaction is -1835 kJ.

3 0
4 years ago
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