Answer:
T final = 80°C
Explanation:
∴ Q = 18000 cal
∴ m H2O = 300 g
∴ Cp H2O (15°C) = 0.99795 cal/g.K ≅ 1 cal/g.K
∴ T1 = 20°C = 293 K
∴ T2 = ?
⇒ 18000 cal = (300 g)(1 cal/g.K)(T2 - 293 K)
⇒ (18000 cal)/(300 cal/K) = T2 - 293 K
⇒ T2 = 293 K + 60 K
⇒ T2 = 353 K (80°C)
Principal quantum number
magnetic quantum number
subsidiary quantum number
spin quantum number
Answer:
Explanation:
volume of solution = 100 + 100 = 200 mL
mass of reaction mixture = 200 x 1.010 = 202 g
specific heat of solution mixture = 4.184 J/g-°C
heat evolved = mass x specific heat x rise in temperature
= 202 x 4.184 x 7.01
= 5924.63 J
100 mL of 1 M HCl
= .1 L of 1M HCl will contain .1 mole of HCl
.1 mole reacts with .1 mole of NH₄OH to make 5924.63 J of heat
1 mole reacts with 1 mole of NH₄OH to make 59246.3 J of heat
heat of reaction = 59246.3 J / mol
= 59.246 kJ / mol
= 59.3 kJ / mol .
Basalt, rhyolite, andesite, and obsidian could all be answers.
They help keep track of notes and experaments