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drek231 [11]
3 years ago
12

When might a limited warranty be a better choice than a full warranty?

Mathematics
2 answers:
Basile [38]3 years ago
4 0
Choosing a limited warranty may be a better choice (compared to a full warranty) when you are unsure of your plans in the future and may want to cancel your purchase.

Also, f you don't have a lot of money at the moment, but you still want to be covered by a warranty, choose a limited warranty as they cost less.
Paul [167]3 years ago
4 0

Answer:

A limited warranty can be more economical than a full warranty. If the conditions excluded by the limited warranty are either not very expensive or are exceedingly unlikely to ever arise, but you still want to have some protection for your purchase, a limited warranty can be a better deal.

Step-by-step explanation:

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On a map, the distance bewtween the two towns is 2.5 inches, and 1 inch represents 6 mile. What is the actual distance between t
Lilit [14]

Answer: 15

Step-by-step explanation:

Ratio is 1 inch:6 mile

2.5 inches divided by 1 inch equals 2.5 inches

2.5 inches times 6 equals 15

4 0
3 years ago
Read 2 more answers
Which of the following is solution set of 4x = y and 2x2 − y = 0? A. {(0.5, -0.5), (2, -8)} B. {(0, 0), (2, 8)} C. {(1.5, 2), (8
sergiy2304 [10]
4x = y
2x^2 - y = 0
2x^2 - 4x = 0
2x(x - 2) = 0
2x = 0 or x - 2 = 0
x = 0 or x = 2

y = 4(0) or y = 4(2)
y = 0 or y = 8

Therefore, solution set is {(0, 0), (2, 8)}
7 0
3 years ago
Find the value of x. 10_3 
Lisa [10]
67^o;\ 90^o\ and\ x^o\\angles\ on\ one\ side\ of\ a\ straight\ line\\will\ always\ add\ to\ 180^o.\\\\67^o+90^o+x^o=180^o\\157^o+x^o=180^o\ \ \ \ |subtract\ 157^o\ from\ both\ sides\\\boxed{x^o=23^o}
3 0
3 years ago
Please Help! Multiple Choice!
Katyanochek1 [597]

Using the z-distribution, the p-value would be given as follows:

b) 0.0086.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis we test if the means are equal, hence:

H_0: \mu_D - \mu_C = 0

At the alternative hypothesis, it is tested if they are different, hence:

H_1: \mu_D - \mu_C \neq 0

<h3>What are the mean and the standard error for the distribution of differences?</h3>

For each sample, they are given as follows:

  • \mu_D = 12, s_D = \frac{5.2}{\sqrt{73}} = 0.6086
  • \mu_C = 14, s_C = \frac{4.1}{\sqrt{81}} = 0.4556

Hence, for the distribution of differences, they are given by:

  • \overline{x} = 12 - 14 = -2.
  • s = \sqrt{0.6086^2 + 0.4556^2} = 0.76

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

z = \frac{\overline{x} - \mu}{s}

z = \frac{-2 - 0}{0.76}

z = -2.63.

Using a z-distribution calculator, for a two-tailed test, with z = -2.63, the p-value is of 0.0086.

Hence option B is correct.

More can be learned about the z-distribution at brainly.com/question/13873630

#SPJ1

4 0
2 years ago
Pls help me with this
katovenus [111]

Answer:

5.85

Step-by-step explanation:

100%-> 6.50

100%-10% = 90 %

90%-> 6.50/100 x 90

           =5.85

8 0
2 years ago
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