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cricket20 [7]
3 years ago
13

How can you use a number line to find the sum of -4 and positive 6

Mathematics
1 answer:
MrRissso [65]3 years ago
3 0
Start at -4 and go over to the right 6. - is left and +is right. the answer is 2.
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I have been stuck on this for days someone pls help!!!!
sdas [7]
Use the Sum of Angles In a Triangle therom.
8 0
3 years ago
Heights of adult males are known to have a normal distribution. a researcher claims to have randomly selected adult males and me
8090 [49]

Answer:

The sum of the probabilities is greater than 100%; and the distribution is too uniform to be a normal distribution.

Step-by-step explanation:

The sum of the probabilities of a distribution should be 100%.  When you add the probabilities of this distribution together, you have

22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121

This is more than 100%, which is a flaw with the results.

A normal distribution is a bell-shaped distribution.  Graphing the probabilities for this distribution, we would have a bar up to 22; a bar to 24; a bar to 21; a bar to 26; and bar to 28.

The bars would not create a bell-shaped curve; thus this is not a normal distribution.

3 0
3 years ago
Read 2 more answers
the sum of three numbers is 128.The third number is 10 more than the first .The second number 4 times the third number. what are
Ray Of Light [21]
128 = a + + 4(a + 10) + (a + 10)
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a

1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23
3 0
3 years ago
How do you complete the square to rewrite y= x^ -6x + 15 in vertex form
Vaselesa [24]
Vertex form of a quadratic equation is y=a(x-h)^{2}+k
where (h, k) is the vertex. 

Our aim is to write the expression y=x^{2} -6x+15 in the form 
y=a(x-h)^{2}+k



y=x^{2} -6x+15

y=x^{2} -2*3*x+15

y=(x^{2} -2*3*x+ 3^{2})-3^{2}+ 15

y=(x-3)^{2}-9+15

y=(x-3)^{2}+6
5 0
3 years ago
Distributive property
lorasvet [3.4K]

So what is the question?

6 0
3 years ago
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