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3 years ago

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Describe the location of the point having the following coordinates. positive abscissa, positive ordinate Quadrant I Quadrant II

Quadrant III Quadrant IV NEXT QUESTION ASK FOR HELP

1 answer:

asambeis [7]3 years ago

8 0

The abscissa is the x coordinate whereas the ordinate is the y coordinate. Both x and y are positive in the first quadrant only.

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Which is the simplified form of (9c^-9)^-3<br> b 1/729 c^27

rosijanka [135]

<u>ANSWER</u>

$(9 {c}^{ - 9} )^{ - 3}=\frac{{c}^{ 27} }{729}$

<u>EXPLANATION</u>

The given expression is

$(9 {c}^{ - 9} )^{ - 3}$

Recall that:

$({a}^{m} )^{n} = {a}^{mn}$

We use the law of exponents to get

$(9 {c}^{ - 9} )^{ - 3} = 9^{ - 3} {c}^{ - 9 \times - 3}$

Let us multiply in the exponents to get:

$(9 {c}^{ - 9} )^{ - 3} = 9^{ - 3} {c}^{ 27}$

Recall again that:

${a}^{ - m} = \frac{1}{ {a}^{m} }$

This implies that:

$(9 {c}^{ - 9} )^{ - 3} = \frac{1}{ {9}^{ 3} } \times {c}^{ 27}$

We expand the power to get:

$(9 {c}^{ - 9} )^{ - 3} = \frac{1}{9 \times 9 \times 9} \times {c}^{ 27}$

$(9 {c}^{ - 9} )^{ - 3}=\frac{1}{729} \times {c}^{ 27}$

We multiply out to get:

$(9 {c}^{ - 9} )^{ - 3}=\frac{{c}^{ 27} }{729}$

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Step-by-step explanation:

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