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BabaBlast [244]
3 years ago
7

A capacitor with C = 6.00 μF is fully charged by connecting it to a battery that has emf 50.0 V. The capacitor is disconnected f

rom the battery. A resistor of resistance R = 185 Ω is connected across the capacitor, and the capacitor discharges through the resistor.
What is the charge q on the capacitor when the current in the resistor is 0.180 A?
Physics
1 answer:
Arte-miy333 [17]3 years ago
4 0

Answer:

1.99×10^-4coulombs

Explanation:

The charge (Q) across the resistor the directly proportional to the voltage (V) where capacitance of the capacitor(C) is the proportionality constant. Mathematically, Q = CV

If V is the voltage across the resistor, V = IR (according to ohm's law) where I is the current in the resistor and R is the resistance.

We need to calculate the voltage on the resistor first when 0.18A current is passed through it.

V = 0.18 × 185

V = 33.3Volts

The charge Q on the resistor will be;

Q = CV

Were C = 6.00 μF, V = 33.3

Q= 6×10^-6 ×33.3

Q = 0.0001998

Q= 1.99×10^-4Coulombs

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Answer:

<em>The velocity of the truck is 3.33 m/s</em>

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<u>Law Of Conservation Of Linear Momentum </u>

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m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

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Given that a  1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail

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