Answer:
Applied voltage should be 13.5396 kV
Explanation:
The charge stored by a capacitor when subjected to a potential difference 'v' across it's plates is given by
Solving for V we get
thus to store a charge of 0.11mC we solve for V as follows
Applying values we get
Answer:
Action - Pulling up the train.
Reaction - Friction on the locomotive
Explanation:
Locomotive is pulling the train upwards ,
Which is the action force applied by the locomotive,
As a reaction locomotive will be pulled by the train which is the reaction of pulling
Now, considering it as a action on locomotive , friction force will act on it as a reaction upwards which will result to move it upwards.
For train action is pulling up by locomotive and reaction will be friction acting on it downwards.
The author mentions that Shine made several mistakes in her experiment. Describe one major mistake that Shine made.
First, let us assign the variables
y = 0.90 m, x= 15 m,
= 2.80 m
s= required
The vertical component of the trajectory is in uniformly accelerated motion. The equation is:
, while the horizontal component is
. Also,
since the object starts from rest (with respect to the downward motion). a is negative because it is moving downwards (a = -9.81 m/s^2). Substituting,
The magnitude of v0, which is speed (s), is equal to 24.1 m/s
Explanation:
a)
The circumference of the path is:
C = 2πr
C = 2π (0.235 m)
C = 1.48 m
Velocity = displacement / time
v = 1.48 m / 1.95 s
v = 0.757 m/s
b)
1 rev / 1.95 s = 0.513 Hz
c)
1 rev / 1.95 s × (2π rad / rev) = 3.22 rad/s