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Flauer [41]
3 years ago
5

Which of the following terms represents the debate between genetic and environmental influences on behavior?

Physics
1 answer:
katrin [286]3 years ago
5 0

Answer:

I believe it is nature vs nurture

Explanation:

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Add a picture of leaves.
iren2701 [21]

Answer:

There you go

Explanation:

 

6 0
4 years ago
How to calculate ?Help!!!
Alona [7]
How to calculate what?
6 0
4 years ago
A day on a distant planet observed orbiting a nearby star is 21.5 hr. Also, a year on the planet lasts 69.3 Earth days. In other
serg [7]

Answer:

Part A

The angular speed of rotation of the plane is 8.11781 × 10⁻⁵ rad/s

Part B

The angular speed of orbit of the planet is 1.04938 × 10⁻⁶ rad/s

Explanation:

The parameters of the planet are;

The duration of a day on the distant planet = 21.5 hr.

The duration of a year on the distant planet = 69.3 Earth days

Part A

The duration of a day = The time to make one complete revolution of 2·π radians

∴ The average angular speed about its axis, \omega_{rotation} = Angle turned/Time

∴ \omega_{rotation}  = 2·π/(21.5 × 60 × 60) s ≈ 8.11781 × 10⁻⁵ rad/s

The average angular speed of the planet about its own axis, \omega_{rotation}  = 8.11781 × 10⁻⁵ rad/s

The angular speed of rotation of the plane \omega_{rotation}  = 8.11781 × 10⁻⁵ rad/s

Part B

The time it takes the planet to revolve round the neighboring star once = 69.3 Earth days

Therefore, the average angular speed of the planet around its neighboring star, \omega _{Star}, is given as follows;

\omega _{Orbit}  = 2·π/((69.3 × 24 × 60 × 60) s) = 1.04938 × 10⁻⁶ rad/s

The average angular speed of orbit, \omega _{Orbit} = 1.04938 × 10⁻⁶ rad/s

The angular speed of orbit of the planet, \omega _{Orbit} = 1.04938 × 10⁻⁶ rad/s.

3 0
3 years ago
When multiple light waves overlap and cause patterns of bright and dark areas it is called wave ?
dmitriy555 [2]

Answer: Interference

Explanation:

3 0
4 years ago
a skier speeds along a flat patch of snow, and then flies horizontally off the edge at 16.0 m/s. He eventually lands on a straig
geniusboy [140]

Answer:

1.63 s

Explanation:

The skier lands on the sloped section when the direction of its velocity is exactly identical to that of the slope, so at 45.0^{\circ} below the horizontal.

This occurs when the magnitude of the vertical velocity is equal to the horizontal velocity (in fact, \tan \theta =\frac{|v_y|}{v_x}, and since \theta=45.0^{\circ}, tan \theta = 1 and so |v_y| = v_x.

We already know the horizontal velocity of the skier:

v_x = 16.0 m/s

And this is constant during the entire motion.

The vertical velocity instead is given by

v_y = u_y + gt

where

u_y = 0 is the initial vertical velocity (zero since the skier flies off horizontally)

g = 9.8 m/s^2

t is the time

Here we have chosen the downward direction as positive direction.

Substituting v_y = 16.0 m/s, we find the time:

t=\frac{v_y}{g}=\frac{16.0}{9.8}=1.63 s

5 0
3 years ago
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