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Basile [38]
3 years ago
5

The BMI of someone that weights 121 pounds and is 64 inches tall:

Physics
2 answers:
nordsb [41]3 years ago
8 0

Answer:

B

;)

Explanation:

Ainat [17]3 years ago
7 0

Answer:

B - 32.52

Explanation:

Hope this Helps!

:)

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Boyle's Law states that as the pressure on a gas increases at constant temperature the volume of the gas
elena55 [62]
Boyle’s law is P1V1 = P2V2. This shows that pressure and volume have an inverse relationship, so increase in pressure causes a decrease in volume. B is your answer
4 0
3 years ago
How can an athlete participating in a 40m sprint modify and improve their performance based on the kinematic variable of speed a
aleksandrvk [35]

The athlete can improve performance by building strength, coordination and balance.

<h3>Who is an Athlete?</h3>

This is an individual who is proficient in sports and other forms of physical exercise.

Improvement of performance based on the kinematic variable of speed and acceleration can be achieved by building strength, coordination and balance by performing plyometric exercises etc.

Read more about Athlete here brainly.com/question/1532968

5 0
3 years ago
(d)
deff fn [24]

Answer:

Frequency = 24 × 10⁸ Hz

Explanation:

Given the following data;

Speed = 3 × 10⁸ m/s

Wavelength = 0.125 meters

To find the frequency of the electromagnetic wave;

Mathematically, the speed of a wave is given by the formula;

Speed = Wavelength × frequency

Substituting into the formula, we have;

3 × 10⁸ = 0.125 × frequency

Frequency = (3 × 10⁸)/0.125

Frequency = 24 × 10⁸ Hz

3 0
3 years ago
A certain electric dipole consists of charges q and –q separated by distance d, oriented along the x-axis as shown in the figure
Anna71 [15]

Electric field due to a point charge is given by formula

E = \frac{kq}{r^2 + \frac{d^2}{4}}

now due to negative charge also the magnitude of electric field will be same

only difference is the direction of field due to negative charge is radially inwards

now we can say that net field due to these two charges is given as

E = 2E_0cos\theta

E = 2\frac{kq}{r^2 + \frac{d^2}{4}}*\frac{d/2}{\sqrt{r^2 + \frac{d^2}{4}}}

E = \frac{kqd}{(r^2 + \frac{d^2}{4})^1.5}

now it is given that distance r is very large than "d" so we can say

E = \frac{kqd}{r^3}

<em>so above is the electric field due to dipole</em>

7 0
3 years ago
What profession is most likely to make use of amphoras and candelas
Monica [59]
Biologists probably
5 0
3 years ago
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